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slava [35]
3 years ago
10

The means and mean absolute deviations of the individual times of members of two relay swim teams are shown in the table below.

Means and Mean Absolute Deviations of Individual Times of Members of mc011-1.jpg Relay Swim Teams Team A Team B Mean 127.9 s 127.4 s Mean Absolute Deviation 0.26 s 0.23 s The difference of the means is found and then compared to each of the mean absolute deviations. Which is true? The difference between the mean times is about equal to the mean absolute deviation of the data sets. The difference between the mean times is about 2 times the mean absolute deviation of the data sets. The difference between the mean times is about 5 times the mean absolute deviation of the data sets. The difference between the mean times is about 16 times the mean absolute deviation of the data sets.

Mathematics
2 answers:
I am Lyosha [343]3 years ago
8 0

Answer:

B should be be your answer

Step-by-step explanation:


shepuryov [24]3 years ago
7 0
See the attached picture for the solution:

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il63 [147K]
The answer is B.She subtracted the GCF from the second term in the expression instead of dividing.

Incorrect:
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3 years ago
Determine the growth factor corresponding to 325% increase
Aleks [24]

Answer:

  4.25

Step-by-step explanation:

The growth factor is 1 more than the growth rate. The growth rate is the rate of increase in a given time period.

  1 +325% = 1 +3.25 = 4.25

The growth factor is 4.25.

_____

The "increase" amount is what is added to the original. The growth factor is the multiplier of the original.

  x + 325%·x = x(1 +3.25) = 4.25x

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Which of the following conditions must be met in order to make a statistical inference about a population based on a sample if t
Nadusha1986 [10]

Answer:

The answer is letter C.

6 0
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4 0
3 years ago
Help me please this was due yesturday​
stepan [7]

Step-by-step explanation:

<em>Slope</em><em> </em><em>intercept</em><em> </em><em>form</em><em> </em><em>is</em>

<em>y = mx + b</em>

<em>where</em><em> </em><em>m</em><em> </em><em>is</em><em> </em><em>the</em><em> </em><em>slope</em><em>(</em><em> </em><em>average</em><em> </em><em>rate</em><em> </em><em>of</em><em> </em><em>change</em><em>)</em><em> </em><em>and</em><em> </em><em>b</em><em> </em><em>is</em><em> </em><em>the</em>

<em> </em><em>y</em><em> </em><em>intercept</em><em>(</em><em> </em><em>the</em><em> </em><em>y</em><em> </em><em>value</em><em> </em><em>when</em><em> </em><em>x</em><em> </em><em>is</em><em> </em><em>zero</em><em>)</em><em>.</em>

<em>When</em><em> </em><em>x</em><em>=</em><em>0</em><em>,</em><em> </em><em>y</em><em> </em><em>is</em><em> </em><em>2</em><em>.</em><em> </em><em>This</em><em> </em><em>means</em><em> </em><em>b</em><em>=</em><em>2</em>

<em>Slope</em><em> </em><em>is</em><em> </em><em>change</em><em> </em><em>in</em><em> </em><em>y</em><em> </em><em>value</em><em>/</em><em> </em><em>change</em><em> </em><em>in</em><em> </em><em>x</em><em> </em><em>value</em><em>.</em><em> </em><em>Another</em><em> </em><em>obvious</em><em> </em><em>arbitrary</em><em> </em><em> </em><em>point</em><em> </em><em>we</em><em> </em><em>are</em><em> </em><em>given</em><em> </em><em>is</em><em> </em><em>(</em><em>-8</em><em>,</em><em>0</em><em>)</em><em>.</em>

<em>So</em><em> </em><em>let</em><em> </em><em>use</em><em> </em><em>the</em><em> </em><em>formula</em><em> </em><em>we</em><em> </em><em>given</em><em>.</em>

<em>So</em><em> </em><em>our</em><em> </em><em>slope</em><em> </em><em>is</em><em> </em><em>1</em><em>/</em><em>4</em><em> </em><em>so</em><em> </em><em>our</em><em> </em><em>equation</em><em> </em><em>is</em><em> </em>

<em>1</em><em>/</em><em>4x</em><em>+</em><em>2</em>

6 0
3 years ago
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