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slava [35]
3 years ago
10

The means and mean absolute deviations of the individual times of members of two relay swim teams are shown in the table below.

Means and Mean Absolute Deviations of Individual Times of Members of mc011-1.jpg Relay Swim Teams Team A Team B Mean 127.9 s 127.4 s Mean Absolute Deviation 0.26 s 0.23 s The difference of the means is found and then compared to each of the mean absolute deviations. Which is true? The difference between the mean times is about equal to the mean absolute deviation of the data sets. The difference between the mean times is about 2 times the mean absolute deviation of the data sets. The difference between the mean times is about 5 times the mean absolute deviation of the data sets. The difference between the mean times is about 16 times the mean absolute deviation of the data sets.

Mathematics
2 answers:
I am Lyosha [343]3 years ago
8 0

Answer:

B should be be your answer

Step-by-step explanation:


shepuryov [24]3 years ago
7 0
See the attached picture for the solution:

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You made the choice to choose the letter A, a second time.
3 0
3 years ago
Determine if the graph is a function then state the domain and range.
nignag [31]
<h3><u>Explanation</u></h3>

A function is a set of relation that doesn't have repetitive domain. If we want to know if a graph is function or not, we have to do the line test.

<u>Line</u><u> </u><u>Test</u>

  1. Draw a vertical line. Make sure that a line passes through a graph.
  2. See if a line intercepts a graph more than one point or just only one.

<u>Result</u>

If a line intercepts a graph more than one point, it is not a function.

However, if a line only intercepts a graph just one point, it is indeed a function.

The given graph from the question is a function because it passes line test.

<u>Domain</u><u> </u><u>and</u><u> </u><u>Range</u>

Domain is the set of all x-values, meaning we only focus on x-axis or x-value only.

Range is the set of all y-values. We only focus on y-value or y-axis for Range.

<u>Determine</u><u> </u><u>Domain</u><u> </u><u>from</u><u> </u><u>Graph</u>

We can simply say that the domain is from starting domain or x-coordinate point to end x-coordinate point. For example, if a graph starts at x = -4 and ends at x = 2, we can say that - 4<=x=2.

<u>Determine</u><u> </u><u>Range</u><u> </u><u>from</u><u> </u><u>Graph</u>

Similar to Domain except Range starts from the minimum value or point to the maximum point or value. For example if a graph starts at min point = 6 and max point = 9. We can say that 6<=y<=9.

From the graph, the domain starts from negative infinity to positive infinity. Meaning that x can be any numbers. Hence, the domain is set of all real numbers. For range, the minimum value is 0 and max value is positive infinity. Therefore we write y>=0.

<h3><u>Answer</u></h3>

<u>\begin{cases} x \in  \mathbb{R} \\ y \geqslant 0 \end{cases}</u>

<u>Domain</u><u> </u><u>is</u><u> </u><u>set</u><u> </u><u>of</u><u> </u><u>all</u><u> </u><u>real</u><u> </u><u>numbers</u><u>.</u>

<u>Range</u><u> </u><u>is</u><u> </u><u>greater</u><u> </u><u>or</u><u> </u><u>equal</u><u> </u><u>to</u><u> </u><u>0</u><u>.</u>

8 0
3 years ago
A man standing near a building notices trhat the angle of elevation to the top of the buiilding is 64. he then walks 240 feet fa
trasher [3.6K]
See the picture attached to better understand the problem
 we know that
in the right triangle ABC
tan 64°=AB/AC------> AB=AC*tan 64°-----> AB=x*tan 64°---> equation 1

in the right triangle ABD
tan 43°=AB/DA----> AB=DA*tan 43°---> AB=(240+x)*tan 43°---> equation 2

equate equation 1 and equation 2
x*tan 64°-=(240+x)*tan 43°---->x*tan 64=240*tan 43+x*tan 43
x*[tan 64-tan 43]=240*tan 43-----> x=240*tan 43/[tan 64-tan 43]
x=200.22 ft

AB=x*tan 64----> AB=200.22*tan 64-----> AB=410.51 ft

the answer is
410.51 ft

3 0
4 years ago
Given that x = -2 - 3i and y = 4 + 2i , Match The Expressions.
shtirl [24]

Answer:

3y-2x=16+12i

-3x \cdot y=6+48i

x \cdot 2y=-4-32i

x-y=-6-5i

Step-by-step explanation:

Given:

x=-2-3i

y=4+2i

---

1st problem:

3y-2x

3(4+2i)-2(-2-3i)

Distribute:

12+6i+4+6i

Combine like terms:

16+12i

---

2nd problem:

-3x \cdot y

-3(-2-3i) cdot (4+2i)

-3(-2-3i)(4+2i)

Distribute -3 to first factor:

(6+9i)(4+2i)

Use foil to simplify:

24+12i+36i+18i^2

Replace i^2 with -1:

24+48i-18

Combine like terms:

6+48i

---

3rd problem:

x \cdot 2y

(-2-3i) \cdot 2(4+2i)

Distribute 2 to the second factor:

(-2-3i) \cdot (8+4i)

(-2-3i)(8+4i)

Use foil to simplify:

-16-8i-24i-12i^2

Replace i^2 with -1:

-16-32i+12

Combine like terms:

-4-32i

----

4th problem:

(-2-3i)-(4+2i)

Distribute:

-2-3i-4-2i

Combine like terms:

-2-4-3i-2i

Simplify:

-6-5i

6 0
3 years ago
Read 2 more answers
Find the median of these job salaries
dsp73

Answer:

Step-by-step explanation:

the answer is 40000

3 0
3 years ago
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