I think b not sure it’s the only one that makes sense
i. 171
ii. 162
iii. 297
Solution,
n(U)= 630
n(I)= 333
n(T)= 168
i. Let n(I intersection T ) be X
<h3>ii.
n(only I)= n(I) - n(I intersection T)</h3><h3>
= 333 - 171</h3><h3>
= 162</h3>
<h3>
iii. n ( only T)= n( T) - n( I intersection T)</h3><h3>
= 468 - 171</h3><h3>
= 297</h3>
<h3>
Venn- diagram is shown in the attached picture.</h3>
Hope this helps...
Good luck on your assignment...
Answer:
m∠MON = 15°
Step-by-step explanation:
The given parameters are;
m∠LON = 77°
m∠LOM = 9·x + 44°
m∠MON = 6·x + 3°
By angle addition postulate, we have;
m∠LON = m∠LOM + m∠MON
Therefore, by substituting the known values, we have;
∴ 77° = 9·x + 44° + 6·x + 3°
77° = 9·x + 44° + 6·x + 3° = 15·x + 47°
77° = 15·x + 47°
77° - 47° = 15·x
15·x = 77° - 47° = 30°
15·x = 30°
x = 30°/15 = 2°
x = 2°
Given that m∠MON = 6·x + 3° and x = 2°, we have;
m∠MON = 6 × 2° + 3° = 12° + 3° = 15°
m∠MON = 15°.
Answer:
She will make 217.50 for 29 hours
Step-by-step explanation:
We can find the rate per hour by dividing the money by the number of hours
90/12 =7.5 per hour
She makes 7.50 per hour
If she works 29 hours
Money = rate * hours
= 7.5 * 29
=217.50
She will make 217.50 for 29 hours
