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choli [55]
3 years ago
12

Evaluate. (jk−1)÷j when j=−4 and k=−0.7 Enter your answer as a decimal in the box.

Mathematics
1 answer:
Helga [31]3 years ago
5 0

Answer:

(jk - 1) / j

jk = (-4 x -0.7) = 2.8

(2.8 - 1) / - 4

1.8 / -4 = -0.45

Answer is -0.45 when j = -4 and k = -0.7

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BRAINLIEST <br> Solve for X. Round to the nearest tenth.
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7 0
2 years ago
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.................................

6 0
3 years ago
Which of the following is a solution of x^2 - 7x = -5
Oduvanchick [21]

Answer: B) 7 + or - the square root of 29 all over 2

Which of the following is a solution of x^2 - 7x = -5

A) 7 + or - the square root of 69 all over 2

B) 7 + or - the square root of 29 all over 2

C) -7 + or - the square root of 29 all over 2

D) -7 + or - the square root of 69 all over 2

Step-by-step explanation:

I just did the assignment and the correct answer is B) 7 + or - the square root of 29 all over 2! Hope this helps.

Good Luck!!

6 0
3 years ago
EF is tangent to circle P at G (1,-3). If the slope of EF is 7/9, what is the slope of GP?
pentagon [3]
The center of the circle is at P. 
The tangent EF is tangent to the circle at point G. So GP will be the radius of the circle. 

The slope of tangent EF = 7/9

The tangent of a circle is always perpendicular to the radius at the point where it touches the circle. So we can say that EF is perpendicular to GP.

The product of slopes of two perpendicular line is always equal to -1.

Slope of EF x Slope of GP = -1
So,

Slope of GP = - 1 / (Slope of EF)

Thus slope of GP = - 9/7
7 0
3 years ago
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