R2(<span>cos2</span>ϕ−<span>sin2</span>ϕ)−2rcosϕ=0<span><span>r2</span>(<span>cos2</span>ϕ−<span>sin2</span>ϕ)−2rcosϕ=0</span>
<span><span><span>r2</span>cos<span>(2ϕ)</span>−2rcosϕ=0</span><span><span>r2</span>cos<span>(2ϕ)</span>−2rcosϕ=<span>0
Now </span></span></span> divide through by <span><span>r≠0</span><span>r≠0</span></span>
and get
<span><span>rcos<span>2ϕ</span>−2cosϕ=0</span><span>rcos<span>2ϕ</span>−2cosϕ=0</span></span>
or
<span><span>r=2<span><span>cosϕ</span><span>cos<span>2ϕ</span></span></span></span><span>r=2<span><span>cosϕ</span><span>cos<span>2<span>ϕ</span></span></span></span></span></span>
What am I helping ? put the question in
The distance would be 2√3 , in other words it is 2 square root 3
Answer:
The area of the circular ring is 53.73 π sq. yards
Step-by-step explanation:
The diameter of the skating ring = 44 ft
Diameter = 2 x Radius
⇒Radius of the ring = 44 / 2 = 22 ft
Now, 1 ft = 0.333333 yards
⇒22 ft = 22 x 0.333333 yards = 7.3333 yards
Now, Area of the circular Ring = 
or, 
= 53.73 π sq. yards
or, the area of the circular ring is 53.73 π sq. yards
