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2 years ago

What is the range of possible sizes for side x

Mathematics

2 answers:

sdas [7]2 years ago

6 0

Answer:

maybe 9-10

Step-by-step explanation:

vladimir1956 [14]2 years ago

5 0

Answer:

4<x<12

Step-by-step explanation:

8.0+4.0=12.0

8.0-4.0=4.0 or 4

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A river flows at 2m/s. Juan’s boat can travel twice as fast down the river as it can go up the river. How fast can the boat go i

solniwko [45]

Answer: 2m/s

Step-by-step explanation:

The boat goes twice as fast down the river, which means it goes twice as slow up the river.

Because the river flows at 2m/s, I think the answer is 2m/s

6 0

1 year ago

Jamie's car is 9 yards long. Joey's car is 27 feet long. When you line them up one in front of the other, how long are they toge

Softa [21]

Answer:

Step-by-step explanation:

9 x 3 = 27

27 + 27 = 54

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2 years ago

Solve the equation using square roots.<br><br> <img src="https://tex.z-dn.net/?f=4x%5E%7B2%7D%20%2B9%3D0" id="TexFormula1" title

aleksklad [387]

Isolating the variable terms and dividing by 4, we have $x^2=-\frac{9}{4}.$ Taking the square root, we have $\boxed{x=\frac{3i}{2},-\frac{3i}{2}}.$

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3 years ago

Find the absolute value.<br> What is the absolute value of four

iren [92.7K]

Answer:

whats the graph???

Step-by-step explanation:

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2 years ago

A square pyramid has a base with an area of 20 square meters, and its lateral faces have a slant height of x meters. Sydney is c

svetoff [14.1K]

1. Consider the pyramid ABCDE in the figure 1 attached:

Each side of the square base equals $\sqrt{20} = \sqrt{4*5} = \sqrt{4}* \sqrt{5}=2 \sqrt{5}$ (units)

Area of 1 lateral side of pyramid ABCDE is $\frac{1}{2}* 2 \sqrt{5}*x=\sqrt{5}x$

so the total lateral area is $4\sqrt{5}x$ (units squared)

and the total surface area is $20+4\sqrt{5}x$ (units squared)

2. Now consider the second figure KLMNP, Sydney's pyramid:

The lateral area is $4* \frac{1}{2}* 4 \sqrt{5} *2x=16 \sqrt{5}x$

so the total area of the second pyramid is $20+16 \sqrt{5}x$

So 2 things can be said about the areas:

i) the lateral area of Sydney's pyramid is $\frac{16 \sqrt{5}x}{4\sqrt{5}x} =4$ times larger than the lateral area of the original pyramid.

ii) The total area of Sydney's pyramid is $(20+16 \sqrt{5}x)-(20+4\sqrt{5}x)=12\sqrt{5}x$ units squared larger than the total area of the original pyramid.

5 0

3 years ago

Read 2 more answers