All categories

3 years ago

A rectangle has a length of 6 inches and a width of 3 inches.

Mathematics

2 answers:

White raven [17]3 years ago

6 0

Answer: the answer is a

Step-by-step explanation:

the dimensions are being multiplied by a 8

3+3+6+6=18

3 times 8 is 24 and 6 times 8 is 48

42+24+48+48=144

p=144

144/18=8

lutik1710 [3]3 years ago

5 0

C
6*3=18
6*8= 48 and 3*8=24
24*48= 1152
1152/18=64

You might be interested in

Witch expression is equivalent to (-4y-x)-3y-9x)

sleet_krkn [62]

answer: -10x-7y

because you have to simplify the problem

7 0

3 years ago

Find the area of this figure.

umka2103 [35]

Rectangle

l = 7.2 - 1.7 = 5.5 ft b = 3.4 ft

Semicircle

r = 1.7 ft

Shaded region = area of rectangle + area of semicircle

= l x b + πr²/2

= 5.5 x 3.4 + 3.14 x 1.7 x 1.7 x 1/2

= 18.7 + 4.5373

= 23.2373 ft²

6 0

3 years ago

Sin tita= 0.6892.find the value Of tita correct to two decimal places<br><br>

Anvisha [2.4K]

Answer:

$\theta \approx 6.28n + 2.38, \quad n \in \mathbb{Z}$

$\theta \approx 6.28n + 0.76, \quad n \in \mathbb{Z}$

Considering $\theta \in (0, 2\pi]$

$\theta \approx 2.38$

$\theta \approx 0.76$

Step-by-step explanation:

$\sin(\theta)=0.6892$

We have:

$\sin (x)=a \Longrightarrow x=\arcsin (a)+2\pi n \text{ or } x=\pi -\arcsin (a)+2\pi n \text{ as } n\in \mathbb{Z}$

Therefore,

$\theta= \arcsin (0.6892)+2\pi n, \quad n \in \mathbb{Z}$

$\theta = \pi -\arcsin (0.6892)+2\pi n, \quad n\in \mathbb{Z}$

---------------------------------

$\theta \approx 6.28n + 2.38, \quad n \in \mathbb{Z}$

$\theta \approx 6.28n + 0.76, \quad n \in \mathbb{Z}$

4 0

3 years ago

Find the area of each figure

prohojiy [21]

Answer:

A=120

B=20

C=20

Total area=160 cm2

This is really weird because the numbers dont look proportional to the shape but according to the data it should be correct :/

5 0

2 years ago

Read 2 more answers

Help with number 4 please?

LekaFEV [45]

10 because 7 x 3 = 21 and 7 + 3 = 10 so your answer is 10

5 0

3 years ago

Read 2 more answers