Answer:
The graph of y = f(x) will shift to the right 9 units.
Step-by-step explanation:
Despite some lack of clarity, because usually this equality is in terms of x and y. Let's do it.
Taking f(x) as its parent function in other words
Testing some values:
x|y
0|0
1|1
2|2
Adding to the function -9 units is to shift it to the right
Testing some values to certify:
x|y
-9|0-9
-8|1-9
-7|2-9
For this problem, the most accurate is to use combinations
Because the order in which it was selected in the components does not matter to us, we use combinations
Then the combinations are
n represents the amount of things you can choose and choose r from them
You need the probability that the 3 selected components at least one are defective.
That is the same as:
(1 - probability that no component of the selection is defective).
The probability that none of the 3 selected components are defective is:
Where is the number of ways to select 3 non-defective components from 117 non-defective components and
is the number of ways to select 3 components from 120.
So:
Finally, the probability that at least one of the selected components is defective is:
P = 7.4%