Answer:
![\sqrt[5]{2^4}](https://tex.z-dn.net/?f=%5Csqrt%5B5%5D%7B2%5E4%7D)
Step-by-step explanation:
Maybe you want 2^(4/5) in radical form.
The denominator of the fractional power is the index of the root. Either the inside or the outside can be raised to the power of the numerator.
![2^{\frac{4}{5}}=\boxed{\sqrt[5]{2^4}=(\sqrt[5]{2})^4}](https://tex.z-dn.net/?f=2%5E%7B%5Cfrac%7B4%7D%7B5%7D%7D%3D%5Cboxed%7B%5Csqrt%5B5%5D%7B2%5E4%7D%3D%28%5Csqrt%5B5%5D%7B2%7D%29%5E4%7D)
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In many cases, it is preferred to keep the power inside the radical symbol.
Answer:
tall candles = 39
Short candles = 52
Step-by-step explanation:
let tall candles be x
and short candles be y
No. Of candles sold = x + y =91
Money made from candles will be equal to = 8x + 5y = $572
These both are simultaneous linear equations.
x + y =91 ( multiply by 5)
5x + 5y = 455
8x + 5y = $572
Subtract them:
-3x = -117
x = -117/3
x = 39
put value of x in
x + y = 91
39 + y = 91
y = 91 - 39
y = 52
x shows tall candles so they are 39
y shows short candles so they are 52
Answer:
(a) 2min/15units
(b) 1min/20units
(c) The bottleneck stage is cutting. The process capacity is 450units/hour
(d) The capacity of the new employee should be 1unit/2sec. The process capacity will increase four times
Step-by-step explanation:
(a) Cycle time for stage cutting for 2 employees = 16sec/2units × 1min/60sec = 2min/15units
(b) Cycle time for stage sealing for 1 employee = 3sec/1unit × 1min/60sec = 1min/20units
(c) Process capacity of stage cutting = 15units/2min × 60min/1hour = 450units/hour
(d) If the capacity of the new employee is 1unit/2sec, the process capacity = 1unit/2sec × 3600sec/1hour = 1800units/hour. The process capacity increases 4 times (1800/450 = 4)
Answer:
the dog was born on july 30th so the dog would be 3 months and a week old
Step-by-step explanation:
