What is the best description of the translation of pre-image ABC to image A'B'C'? A'B'C'
1 answer:
Answer:
the translation is 4 units at right and 2 units up
Step-by-step explanation:
see the attached figure to better understand the problem
looking at the graph
we have
The coordinates of the pre-image ABC are
A(-1,1),B(2,2),C(1,-1)
The coordinates of the image A'B'C' are
A'(3,3),B'(6,4),C'(5,1)
so
A(-1,1) ----> A'(3,3)
A(-1,1) ----> A'(-1+a,1+b)
-1+a=3 ---> a=3+1=4
1+b=3 ---> b=3-1=2
The rule of the translation is
(x,y) ----> (x+4,y+2)
That means ----> the translation is 4 units at right and 2 units up
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Answer:
Therefore the slope of the line that passes through the points (-9, -8),(−15,−16) is
Step-by-step explanation:
Given:
Let,
point A( x₁ , y₁) ≡ ( -9 ,-8)
point B( x₂ , y₂ )≡ (-15 ,-16)
To Find:
Slope = ?
Solution:
Slope of Line Segment AB is given as
Substituting the values we get
Therefore the slope of the line that passes through the points (-9, -8),(−15,−16) is