Answer:
Below.
Step-by-step explanation:
f(x)=3x^2-6x-45/x^2-5x
= 3x^2-6x-45 / (x(x - 5))
The denominator is zero when x - 0 and x = 5.
So there will be a vertical asymptote at x = 0 and a hole at x = 5.
If we do the division we get f(x) = 3 remainder 9x - 45
so there will also be a horizontal asymptote where x = 3.
Answer:
f(x) = - 4x² + 24x - 20
Step-by-step explanation:
Given
f(x) = - 4(x - 3)² + 16 ← expand the factor using FOIL
= - 4(x² - 6x + 9) + 16 ← distribute parenthesis by - 4
= - 4x² + 24x - 36 + 16 ← collect like terms
= - 4x² + 24x - 20
|RZ|=0.5|SW| therefore 2|RZ|=|SW|.
5x - 20 = 2 · 30
5x - 20 = 60 |add 20 to both sides
5x = 80 |divide both sides by 5
x = 16
Answer:
y = 30
Step-by-step explanation:
We can use ratio's to solve this
40 20
----- = -----------
100 20 + y
Using cross products
40 * (20+y) = 20*100
Distribute
800 + 40y = 2000
Subtract 800 from each side
40y = 2000-800
40y = 1200
Divide by 40
y = 1200/40
y =30
