Two sets (or three technically)
sets {2, 4, 6, 8, 10} & {8,9,10}
The probability of one of the above numbers because it is a union of those two vars/sets so numbers from either set go
{2, 4, 6, 8, 9, 10}
Thats 6 of the 10 numbers
6/10
.6
If i'm wrong, sorry, haven't done this kind of stuff in a while
12÷3=4
cause 1/3 in this situation is 3 cause 12÷4 is 3
Answer:
Logan played for 22 minutes during the second half.
Step-by-step explanation:
Since Keith played the first 22 minutes of a soccer game and Logan then replaced him for the rest of the half, and Logan started the second half and was replaced by Wilson with 18 minutes left in the game, if each half is 40 minutes long To determine how long did Logan play during the second half, the following calculation must be performed:
Second Half Total - Time Played by Wilson = Time Played by Logan
40 - 18 = X
22 = X
Therefore, Logan played for 22 minutes during the second half.
2x - 6 = 14
Add 6 to both sides to isolate the x
2x = 20
Divide 2 to both sides since x is multipled to x
x = 10
To check your work plug 10 into the equation
2(10) -6 = 14
20 - 6 = 14
14 = 14
and it works
