What is the solution to this system of equations? (I suggest using the elimination method by multiplying the first equation by 3 .) 2x + y = 20 6x - 5y = -4 Points earned for putting your solution as an ordered pair. If work is shown, partial credit can be earned. Question 3 options:
2 answers:
Answer:
(6,8)
Step-by-step explanation:
2x + y = 20
6x - 5y = -4
Multiply the first equation by -3
-3(2x + y) = -3*20
-6x -3y = -60
Add this to the second equation
-6x-3y = -60
6x - 5y = -4
--------------------
-8y = -64
Divide each side by -8
-8y/-8 = -64/-8
y = 8
Now find x
2x+y = 20
2x +8 = 20
2x+8-8 = 20-8
2x = 12
Divide by 2
2x/2 = 12/2
x = 6
(6,8)
Answer:
(6,8)
Step-by-step explanation:
2x + y = 20 (1)
6x - 5y = -4 (2)
Multiplying EQ 1 by 5
=> 5(2x + y) = 5(20)
=> 10x + 5y = 100 (3)
On adding 2 and 3
=> 6x - 5y + 10x + 5y = -4 + 100
=> 16x = 96
=> x = 96/16
=> x = 6
From 1
=> 2(6) + y = 20
=> 12 + y = 20
=> y = 20 - 12
=> y = 8
In pair
(x,y) = (6,8)
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