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patriot [66]
3 years ago
12

Solve the equation 3(2x+9)=30

Mathematics
2 answers:
MakcuM [25]3 years ago
5 0

Answer:

x=1/2

Step-by-step explanation:

3(2x+9) = 30

Multiply out the 3

6x + 27 = 30

Subtract 27 on both sides

6x = 3

Divide by 6 on both sides

x = 1/2

Delicious77 [7]3 years ago
5 0

Answer:

x=1/2

Step-by-step explanation

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EFGH is a rhombus. Given EG = 16 and FH = 12, what is the length of one side of the rhombus?
Black_prince [1.1K]

Answer:

(C) 10 units

Step-by-step explanation:

It is given that EFGH is a rhombus and EG = 16 and FH = 12.

We know that the diagonals of the rhombus are the perpendicular bisectors, therefore OF=6, OH=6, OE=8 and OG=8.

Now, using the Pythagoras theorem in ΔOFG, we have

(FG)^{2}=(OG)^{2}+(OF)^{2}

(FG)^{2}=(8)^{2}+(6)^{2}

(FG)^2=64+36

FG=\sqrt{100}

FG=10

Thus, the value of the side of the rhombus will be 10 units.

Hence, option C is correct.

3 0
3 years ago
Read 2 more answers
Show work for this scientific notation
Viktor [21]

\frac{5.1*10^{-2}}{4.57*10^{-4}} \\=\frac{5.1*10^{2}}{4.57} \\=\frac{5.1}{4.57}*10^{2}\\=1.1*10^{2}

The answer is rounded to the nearest tenth.

7 0
3 years ago
match each pair of points with the approximate distance between them. Round your answers to the nearest tenth.
NARA [144]
I hope it helps you.
6 0
3 years ago
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Iodine-131 has a half-life of 8 days. How much would be left of an original 40 g sample after 40 days?
Yuri [45]

Answer:

d) 1.25 g

Step-by-step explanation:

If it has a half life of 40 days, there will be 5 half-lives in that span of time so if you divide 40 by 2, 5 times or just \frac{40}{2^{5} }, it will equal 1.25.

\frac{40}{2}=20\\

\frac{20}{2} =10

\frac{10}{2} =5

\frac{5}{2} =2.5\\

\frac{2.5}{2} =1.25

8 0
3 years ago
What is the slope of the line that passes through the points (-9,0) and (-17 , 0 ) ​
marishachu [46]

Answer:

\mathrm{Slope=== > 0}

Step-by-step explanation:

Hi student, let me help you out!

<u>.............................................................................................................</u>

<u></u>

First, let's recall the slope formula: \boxed{\mathrm{\cfrac{y2-y1}{x2-x1}}}}, where y2 and y1 are y-coordinates; x2 and x1 are x-coordinates.

Plugin the values: \mathrm{\cfrac{0-0}{-17-(-9)}}.

Upon simplifying, we obtain \mathrm{\cfrac{0}{-17+9}}.

Upon simplifying this further, we obtain \mathrm{\cfrac{0}{-9}}.

0 divided by anything results in 0.

✨ ∴, the slope of this particular line is 0, and this line looks something like this: \rule{200}{1}.

See, it's a horizontal line, with a rise of 0, meaning that it goes up 0 units.

Hope this helped you out! Ask in comments if even the slightest queries arise.

Best Wishes!

\star\bigstar\underline{\underline{\overline{\overline{\textsf{Reach far. Aim high. Dream big.}}}}}\bigstar\star

\underline{\rule{300}{5}}

4 0
2 years ago
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