I re-orders as 4,5,5,7,8,8,8,10,10.
Mean 7.2222222222222
Median 8
Mode 8
Range 6
Minimum 4
Maximum 10
Count n 9
Sum 65
Quartiles Quartiles:
Q1 --> 5
Q2 --> 8
Q3 --> 9
Interquartile
Range IQR 4
Outliers none
<span>10x2y(2x + 3y)
Each term has 10 in it. Plus each term has at least 2 x's and 1y. The parenthesis are what's left over. </span>
Step-by-step explanation:
I will solve your system by substitution.
(You can also solve this system by elimination.)
4x+y=17;4x−3y=−3
Step: Solve4x+y=17for y:
4x+y+−4x=17+−4x(Add -4x to both sides)
y=−4x+17
Step: Substitute−4x+17foryin4x−3y=−3:
4x−3y=−3
4x−3(−4x+17)=−3
16x−51=−3(Simplify both sides of the equation)
16x−51+51=−3+51(Add 51 to both sides)
16x=48
16/x = 48/16
(Divide both sides by 16)
x=3
Step: Substitute 3 for x in y=−4x+17:
y=−4x+17
y=(−4)(3)+17
y=5(Simplify both sides of the equation)
Answer:
x=3 and y=5
Add the numbers: 3+17 = 20
-x + 5 < -1/20
Apply the fraction rule: -a/b = - a/b
-x + 5 < - 1/20
Subtract 5 from both sides
-x + 5 - 5 < 1/20 - 5
Simplify
-x< - 101/20
Multiply both sides by -1 (reverse the inequality)
(-x) (-1) > (-101/20) (-1)
x> 101/20 is the final answer
Answer:
c
Step-by-step explanation:
