Brandon has a rectangular garden. The garden is 24 feet long and 16 feet wide. He wants to increase the size of the

Mathematics

1 answer:

Marta_Voda [28]2 years ago

6 0

Answer:96

Step-by-step explanation:24•16/4

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The shortest side of a polygon of area 196 sq. in. is 4 in. long. Find the area of a similar polygon whose shortest side is 8 in

fenix001 [56]

The correct answer is: " 784 in² " .
_________________________________________
                  {or; write as: " 784 sq. inches " .}.
_________________________________________
      When the side is doubled (in this case, 4 is doubled; 4 * 2 = 8} ; the area is increased by 2² times; that is, by 4 times; so, the area is:
    (196 sq. in) * 4 =   784 sq inches .
_________________________________________

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3 years ago

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Write an inequality that expresses the reason the lengths 5 feet, 10 feet, and 20 feet could not be used to make a triangle. Exp

Anit [1.1K]

The 2 smallest lengths in a triangle have to add up to be greater that the longest side of the triangle. In this case, the longest side is 20. The 2 smallest sides are 5 and 10. 5+10=15, but 15<20. This is why these 3 lengths can’t create a triangle.

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2 years ago

2/7 find the reciprocal

Mars2501 [29]

7/2 is the reciprocal of 2/7

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3 years ago

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Yoko received a $70 gift card for a coffee store. She used it in buying some coffee that cost $7.37 per pound. After buying the

GREYUIT [131]

Answer:

Yoko bought 5 pounds of coffee.

If you want the steps, let me know. Hope this helps!!

Step-by-step explanation:

6 0

3 years ago

Simplify (Are all division) 2+4i 3i 3+2i 4+i 2i^11

Alla [95]

$We\ know:\ i=\sqrt{-1}\to i^2=-1$

$\dfrac{2+4i}{3i}=\dfrac{2+4i}{3i}\cdot\dfrac{3i}{3i}=\dfrac{6i+12i^2}{9i^2}=\dfrac{6i+12(-1)}{9(-1)}\\\\=\dfrac{6i-12}{-9}=\dfrac{2i-4}{-3}=\dfrac{4}{3}-\dfrac{2}{3}i$

$\dfrac{3+2i}{4+i}=\dfrac{3+2i}{4+i}\cdot\dfrac{4-i}{4-i}=\dfrac{(3+2i)(4-i)}{4^2-i^2}\\\\=\dfrac{(3)(4)+(3)(-i)+(2i)(4)+(2i)(-i)}{16-(-1)}=\dfrac{12-3i+8i-2i^2}{16+1}\\\\=\dfrac{12+5i-2(-1)}{17}=\dfrac{12+5i+2}{17}=\dfrac{14+5i}{17}=\dfrac{14}{17}+\dfrac{5}{17}i$

$2i^{11}=2i^{10+1}=2i^{10}i^1=2i^{2\cdot5}i=2i(i^2)^5=2i(-1)^5=2i(-1)=-2i$

$Used:\ (a+b)(a-b)=a^2-b^2$

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3 years ago