<span>
</span>Calculate 3 x 5, which is 15.Since 15 is two-digit, we carry the first digit 1 to the next column.
Calculate 5 x 5, which is 25. Now add the carry digit of 1, which is 26.Since 26 is two-digit, we carry the first digit 2 to the next column.
Bring down the carry digit of 2.
<span>Therefore, 53 x 5 = 265.</span>
recall your d = rt, distance = rate * time.
let's say we have two trains, A and B, A is going at 85 mph and B at 65 mph.
they are 210 miles apart and moving toward each other, at some point they will meet, when that happens, the faster train A has covered say d miles, and the slower B has covered then the slack from 210 and d, namely 210 - d.
When both trains meet, A has covered more miles than B because A is faster, however the time both have been moving, is the same, say t hours.
![\bf \begin{array}{lcccl} &\stackrel{miles}{distance}&\stackrel{mph}{rate}&\stackrel{hours}{time}\\ \cline{2-4}&\\ \textit{Train A}&d&85&t\\ \textit{Train B}&210-d&65&t \end{array}\\\\ \dotfill\\\\ \begin{cases} \boxed{d}=85t\\ 210-d=65t\\[-0.5em] \hrulefill\\ 210-\boxed{85t}=65t \end{cases} \\\\\\ 210=150t\implies \cfrac{210}{150}=t\implies \cfrac{7}{5}=t\implies \stackrel{\textit{one hour and 24 minutes}}{1\frac{2}{5}=t}](https://tex.z-dn.net/?f=%20%5Cbf%20%5Cbegin%7Barray%7D%7Blcccl%7D%20%26%5Cstackrel%7Bmiles%7D%7Bdistance%7D%26%5Cstackrel%7Bmph%7D%7Brate%7D%26%5Cstackrel%7Bhours%7D%7Btime%7D%5C%5C%20%5Ccline%7B2-4%7D%26%5C%5C%20%5Ctextit%7BTrain%20A%7D%26d%2685%26t%5C%5C%20%5Ctextit%7BTrain%20B%7D%26210-d%2665%26t%20%5Cend%7Barray%7D%5C%5C%5C%5C%20%5Cdotfill%5C%5C%5C%5C%20%5Cbegin%7Bcases%7D%20%5Cboxed%7Bd%7D%3D85t%5C%5C%20210-d%3D65t%5C%5C%5B-0.5em%5D%20%5Chrulefill%5C%5C%20210-%5Cboxed%7B85t%7D%3D65t%20%5Cend%7Bcases%7D%20%5C%5C%5C%5C%5C%5C%20210%3D150t%5Cimplies%20%5Ccfrac%7B210%7D%7B150%7D%3Dt%5Cimplies%20%5Ccfrac%7B7%7D%7B5%7D%3Dt%5Cimplies%20%5Cstackrel%7B%5Ctextit%7Bone%20hour%20and%2024%20minutes%7D%7D%7B1%5Cfrac%7B2%7D%7B5%7D%3Dt%7D%20)
Answer:
You just move the decimal so 2
Step-by-step explanation:
Answer:
B = 61°
A = 29°
a = 10
Step-by-step explanation:
We are given;
c = 16, b = 14
Since we are told that C is a right angle, it means that C = 90°
Thus using sine rule, we have;
c/sin C = b/sin B
16/sin 90 = 14/sin B
16/1 = 14/sin B
sin B = 14/16
sin B = 0.875
B = sin^(-1) 0.875
B ≈ 61°
Now, since C is a right angle, it means that c will be the hypotenuse of the triangle.
Thus, from pythagoras theorem, If the other side of the triangle is a, then;
a² + b² = c²
a² + 14² = 16²
a² = 16² - 14²
a² = 256 - 156
a² = 100
a = √100
a = 10
Since we know B and C, we can find A because sum of angles in a triangle is 180°.
Thus;
A = 180 - (B + C)
A = 180 - (61 + 90)
A = 29°
If you would like to know how many minutes were spent on language arts, you can calculate this using the following steps:
60% of 40 minutes = 60% * 40 = 60/100 * 40 = 24 minutes
The correct result would be: 24 minutes were spent on language arts.
