I would recommend taking a picture of the instructions because I am not sure if you need to find the equation of the line that is parallel or perpendicular, so I will do both.
1. (3 , 2); y = 3x - 2
If the line is parallel to the given equation, the slopes have to be the SAME, so the slope(m) is 3
y = mx + b
y = 3x + b
To find b you plug in the point (3, 2) into the equation
2 = 3(3) + b
2 = 9 + b
-7 = b
The equation of the line that is parallel to the given equation is:
y = 3x - 7
To find the equation of the line that is perpendicular to the given equation, the slope has to be the exact opposite of the given slope. (you flip the sign and the number of the given slope to get the perpendicular line's slope)
The given slope is 3, the perpendicular slope is 
y = mx + b

To find b, you plug in the point (3 , 2) into the equation

2 = -1 + b
3 = b
The equation of the line perpendicular to the given equation is:

Recall your d = rt, distance = rate * time.
let's say the boat has a still water rate of "b", and the current has a a rate of "c", ok.... when the boat is going upstream, is not really going "b" fast, is going slower at "b - c", due to the current going in the opposite direction.
when the boat is coming downstream, is not going "b" fast either, is going faster, is going "b + c", due to the current adding speed to it.
we know the trip up was 108 kms, thus the return trip is also 108 kms.

and surely you know how much that is.
what's the boat's speed? well, 36 + c = b.
Sorry but we need the numbers
-30 -29 -28 is the correct answer