Complete Question
Polymer composite materials have gained popularity because they have high strength to weight ratios and are relatively easy and inexpensive to manufacture. However, their nondegradable nature has prompted development of environmentally friendly composites using natural materials. An article reported that for a sample of 10 specimens with 2% fiber content, the sample mean tensile strength (MPa) was 51.1 and the sample standard deviation was 1.2. Suppose the true average strength for 0% fibers (pure cellulose) is known to be 48 MPa. Does the data provide compelling evidence for concluding that true average strength for the WSF/cellulose composite exceeds this value? (Use α = 0.05.)
t=8.169
P-value= ?
Answer:
a) 
b) Hence,We FAil to reject the alternative hypothesis and accept that the true average strength for the WSF/ cellulose composite exceeds 48 MPa.
Step-by-step explanation:
From the question we are told that:
Sample size 
Mean 
Standard deviation 
Significance level is taken as 
t test statistics

Therefore

Critical point



Therefore
P-value from T distribution table

Conclusion

We Reject the Null Hypothesis 
Hence,We FAil to reject the alternative hypothesis and accept that the true average strength for the WSF/ cellulose composite exceeds 48 MPa.
The answer should be D.
The square root of two.
The solutions to the equation are
.
You can find the answer to any quadratic by using the quadratic formula. The formula is below.

Then find a (the number attached to x^2), b (the number attached to x) and c (the constant). This will allow you to plug in and solve.




Answer:
y = 10(1.01)^60
Step-by-step explanation:
The general equation of exponential growth is
y = ab^x
b has to do with the rate of growth.
b = 1 + r, so in this case, b = 1 + 1% = 1 + 0.01 = 1.01.
Now we have
y = a(1.01)^x
a is the initial value, so now we have
y = 10000(1.01)^x
where y is the number of books after x months
Since you need the number of books after 5 years, we must convert 5 years into months.
5 years * (12 months)/year = 60 months
The problem wants the expression in thousands of books, so we divide the initial value by 1000.
Answer: y = 10(1.01)^60