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Natali5045456 [20]
3 years ago
9

In a population, 93% of the people are right-handed, and 7% of the people are left-handed. In each of the last 100 days, 1 perso

n in the population has been randomly stopped on the street, For the first 93 days, the person stopped was right-handed, and for the last 7 days, the person stopped was left-handed. If the same person is allowed to be stopped on more than 1 day, what is the probability that the next person stopped will be right-handed?
Mathematics
2 answers:
BARSIC [14]3 years ago
7 0

Answer:

D or 93%

Step-by-step explanation:


stepan [7]3 years ago
6 0
93% because you completed the original set of 100% with the 93/7 day. You can practically restart the count and have again a 93% chance, as you originally had. 
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Ab over 2 equal 2a minus 1,express a in terms of b
sasho [114]

\frac{ab}{2} = 2a - 1

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3 years ago
What is the equivalent fraction?
Vera_Pavlovna [14]
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3 0
4 years ago
Read 2 more answers
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yawa3891 [41]

Answer:

a. 2

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