Answer:
2over1 multiply by 6over 3then you devide both sides by the given numbers then answer is 6woal number 1out of 6
I believe it's a linear function I could be totally wrong math isn't my strongest subject.
Answer:
B. 1/2
Step-by-step explanation:
If we plug in 0 for z, we get 0/0. Apply l'Hopital's rule.
Now when we plug in 0 for z, we get:
The answer is B, I hope this helps! (don't forget to give brainliest)
Answer:
true, false, true, true
Step-by-step explanation:
The set names in this diagram have nothing to do with exponents, radicals, and polynomials. We'll take the diagram at face value.
(a) The labels on the sets seem to be appropriately placed.
__
(b) "Some" in this context means "any or all of the set". Since all of the circle representing integers is outside the rectangle representing irrational numbers, it is TRUE that some integer are not irrational numbers.
No part of the circle representing whole numbers is inside the rectangle representing irrational numbers, so it is FALSE that some whole numbers are irrational numbers.
A portion of the circle representing integers is outside the circle representing whole numbers, so it is TRUE that some integers are not whole numbers.
Every part of the circle representing whole numbers is inside the rectangle representing rational numbers, so it is TRUE that all whole numbers are rational numbers.
