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Natali5045456 [20]
3 years ago
9

In a population, 93% of the people are right-handed, and 7% of the people are left-handed. In each of the last 100 days, 1 perso

n in the population has been randomly stopped on the street, For the first 93 days, the person stopped was right-handed, and for the last 7 days, the person stopped was left-handed. If the same person is allowed to be stopped on more than 1 day, what is the probability that the next person stopped will be right-handed?
Mathematics
2 answers:
BARSIC [14]3 years ago
7 0

Answer:

D or 93%

Step-by-step explanation:


stepan [7]3 years ago
6 0
93% because you completed the original set of 100% with the 93/7 day. You can practically restart the count and have again a 93% chance, as you originally had. 
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Polymer composite materials have gained popularity because they have high strength to weight ratios and are relatively easy and
inn [45]

Complete Question

Polymer composite materials have gained popularity because they have high strength to weight ratios and are relatively easy and inexpensive to manufacture. However, their nondegradable nature has prompted development of environmentally friendly composites using natural materials. An article reported that for a sample of 10 specimens with 2% fiber content, the sample mean tensile strength (MPa) was 51.1 and the sample standard deviation was 1.2. Suppose the true average strength for 0% fibers (pure cellulose) is known to be 48 MPa. Does the data provide compelling evidence for concluding that true average strength for the WSF/cellulose composite exceeds this value? (Use α = 0.05.)  

t=8.169  

P-value= ?

Answer:

a)  P-value=0

b)  Hence,We FAil to reject the alternative hypothesis and accept that the true average strength for the WSF/  cellulose composite exceeds 48 MPa.

Step-by-step explanation:

From the question we are told that:

Sample size n=10

Mean \=x= 51.3

Standard deviation \sigma=1.2

Significance level is taken as \alpha=0.05

t test statistics

t=8.169

Therefore

P-Value=P(t>8.169)

Critical point

t_{\alpha,df}

\alpha=0.05

df=10-1=>9

Therefore

P-value from T distribution table

P-value=0

Conclusion

P-value (0)< \alpha(0.05)

We Reject the Null Hypothesis H_0

Hence,We FAil to reject the alternative hypothesis and accept that the true average strength for the WSF/  cellulose composite exceeds 48 MPa.

7 0
3 years ago
Which choice is equivalent to the quotient shown here when x &gt; 0?​
kramer
The answer should be D.
The square root of two.
7 0
3 years ago
Read 2 more answers
Solve this quadratic equation. 6x^2 - 2x = 7
sweet-ann [11.9K]

The solutions to the equation are \frac{1 +/- \sqrt{43}}{6}.

You can find the answer to any quadratic by using the quadratic formula. The formula is below.

\frac{-b +/- \sqrt{b^{2}-4ac}}{2a}

Then find a (the number attached to x^2), b (the number attached to x) and c (the constant). This will allow you to plug in and solve.

\frac{2 +/- \sqrt{-2^{2}-4(6)(-7)}}{2(6)}

\frac{2 +/- \sqrt{4 + 168}}{12}

\frac{2 +/- \sqrt{172}}{12}

\frac{1 +/- \sqrt{43}}{6}

8 0
4 years ago
ASAP PLS Joselyn expects her new software company to increase its sales next year 2 3/4 the present value. Write this increase a
viva [34]

Answer:

175% i think

Step-by-step explanation:

7 0
3 years ago
At the beginning of the year, the number of books owned by a library was 10,000. Since then, it has grown by 1% each month.
aleksklad [387]

Answer:

y = 10(1.01)^60

Step-by-step explanation:

The general equation of exponential growth is

y = ab^x

b has to do with the rate of growth.

b = 1 + r, so in this case, b = 1 + 1% = 1 + 0.01 = 1.01.

Now we have

y = a(1.01)^x

a is the initial value, so now we have

y = 10000(1.01)^x

where y is the number of books after x months

Since you need the number of books after 5 years, we must convert 5 years into months.

5 years * (12 months)/year = 60 months

The problem wants the expression in thousands of books, so we divide the initial value by 1000.

Answer: y = 10(1.01)^60

8 0
3 years ago
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