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77julia77 [94]
3 years ago
14

Can someone pls help me w this ASAP PLS!!!!!

Mathematics
1 answer:
Fudgin [204]3 years ago
3 0

Answer:

hththththth

Step-by-step explanation:

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HELPPP PLEASE 20 POINTS<br> What is the area of this face?
MrMuchimi

Answer:

28

Step-by-step explanation:

Calcule a area comple

10*4=40

6*2=12

40-12=28

subtraia o recorte

8 0
4 years ago
(1.1/1.2: Interpolating polynomials) Say we want to find a polynomialf(x) ofdegree 3,f(x) =a0+a1x+a2x2+a3x3,satisfying some inte
Hunter-Best [27]

(a) If

<em>f(x)</em> = <em>a</em>₀ + <em>a</em>₁ <em>x </em>+<em> a</em>₂ <em>x</em> ² + <em>a</em>₃ <em>x</em> ³

then from the given conditions we get the system of equations,

<em>f</em> (-1) = <em>a</em>₀ - <em>a</em>₁<em> </em>+<em> a</em>₂ - <em>a</em>₃ = -1

<em>f</em> (1) = <em>a</em>₀ + <em>a</em>₁<em> </em>+<em> a</em>₂ + <em>a</em>₃ = 2

<em>f</em> (2) = <em>a</em>₀ + 2<em>a</em>₁<em> </em>+ 4<em>a</em>₂ + 8<em>a</em>₃ = 1

<em>f</em> (3) = <em>a</em>₀ + 3<em>a</em>₁<em> </em>+<em> </em>9<em>a</em>₂ + 27<em>x</em> ³ = 5

(b) Similarly, if

<em>f(x)</em> = <em>a</em>₀ + <em>a</em>₁ <em>x </em>+<em> a</em>₂ <em>x</em> ² + <em>a</em>₃ <em>x</em> ³

then

<em>f'(x)</em> = <em>a</em>₁<em> </em>+<em> </em>2<em>a</em>₂ <em>x</em> + 3<em>a</em>₃ <em>x</em> ²

so that the given conditions yield the system,

<em>f</em> (1) = <em>a</em>₀ + <em>a</em>₁<em> </em>+<em> a</em>₂ + <em>a</em>₃ = 0

<em>f'</em> (1) = <em>a</em>₁<em> </em>+<em> </em>2<em>a</em>₂ + 3<em>a</em>₃ = 2

<em>f</em> (2) = <em>a</em>₀ + 2<em>a</em>₁<em> </em>+<em> </em>4<em>a</em>₂ + 27<em>a</em>₃ = 3

<em>f'</em> (2) = <em>a</em>₁<em> </em>+<em> </em>4<em>a</em>₂ + 12<em>a</em>₃ = -1

7 0
3 years ago
1/2 x + 3/4=1 please help me!
Kipish [7]
X=1/2 :)))))))))))))
8 0
3 years ago
Find the equation of the line that contains the point (-1, -4) and is parallel to the line 6x+7y=13 . Write the equation in​ slo
sineoko [7]

Answer:  y=-\dfrac67x-\dfrac{34}{7}

Step-by-step explanation:

Slope-intercept form: y=mx+c   (i) , of linear equations,  m= slope and c= y-intercept of the line.

6x+7y=13in slope intercept form would be :

7y=13-6x\\\\\Rightarrow\ y=\dfrac{-6}{7}x+\dfrac{13}{7}

Comparing to (i) , m = \dfrac{-6}{7}

Slope of parallel lines are equal.

So, slope of required line = m = \dfrac{-6}{7}

Equation of line with slope m and passes through point : (y-b)=m(x-a)

So, equation of required line:

(y-(-4))=\dfrac{-6}{7}(x-(-1))\\\\\Rightarrow\ (y+4)=\dfrac{-6}{7}(x+1)\\\\\Rightarrow\ y+4=\dfrac{-6}{7}x-\dfrac{6}{7}\\\\\Rightarrow\ y=-\dfrac67x-\dfrac{6}{7}-4\\\\\Rightarrow\ y=-\dfrac67x-\dfrac{34}{7}

6 0
3 years ago
HELP ME PLEASEEE!!!!<br> don’t use for points or i’ll report and get ur info.
Vadim26 [7]
-6
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Llgsotsoyeitsiysiits
3 0
4 years ago
Read 2 more answers
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