<span>x^2+10x + 25 = (x + 5)^2
missing = 25
hope it helps</span>
The point of intersection of the two lines is at (1,-1)
<h3>System of equation</h3>
The given system of expression is shown below
x - 2y = 3
5x + 3y = 2
The solution to the system of equation is the point of intersection
From equation 1
x = 3 + 2y
Substitute into 2
5(3+2y) + 3y = 2
15 +10y + 3y = 2
13y = -13
y = -1
Substitute y = -1 into 3
x = 3 + 2y
x = 3+(-2)
x = 1
Hence the point of intersection of the two lines is at (1,-1)
Learn more on system of equation here: brainly.com/question/25976025
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Given:
Consider the completer question is "If ∆BTS≅∆GHD, BS=25, TS=14, BT=31, GD=4x-11, m∠S=56, m∠B=21 and m∠H=(7y+5), find the values of x and y.
To find:
The values of x and y.
Solution:
We have,
(Given)
(CPCTC)
Divide both sides by 4.
In ∆BTS,
(Angle sum property)
Now,
(CPCTC)
Divide both sides by 7.
Therefore, the value of x is 9 and value of y is 14.
Answer:
x= −5
/3
Step-by-step explanation:
Answer:
Y: 0, x:0
Y:1, x: 3
Y: 2, x: 6
Y: 3, x:9
Step-by-step explanation:
Plug in the x to get the y
