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2 years ago

Find the area of the given figure :

Mathematics

1 answer:

lawyer [7]2 years ago

7 0

Answer:

formula for area is length × height

so we have 13+8 ×16+4

21×20 = 420m

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The boxes are shaped as right rectangular prisms. The larger box has a length of 24cm a width of 10 cm, and height of 30cm. The

irina1246 [14]

Answer:

900cm^2

Step-by-step explanation:

24, 10, 30 in half= 12, 5, 15 so, 12*5*15=900cm^2

5 0

3 years ago

Sharon is decreasing the size of a diagram of a leaf that is 30 centimeters long by 10 centimeters wide. If the reduced diagram

ivanzaharov [21]

10 : 30
4: x [x is the length]
10/4=2.5
30/2.5=x=12
length of the diagram is 12cm

5 0

3 years ago

Even more trig ratios see attachment

egoroff_w [7]

Step-by-step explanation:

1. Use the Pythagorean theorem to solve for side KM:

16^2+KM^2=34^2
256+KM^2=1156
KM^2=900
KM=30

2. Cosine is adjacent over hypotenuse, so cosine of M would be KM/34, or 30/34

3. Tangent is opposite over adjacent, so tangent of L will be KM/16, or 30/16

4. Sine is opposite over hypotenuse, so sine of M will be 16/34

5. KM=30, solved for in step 1.

hope this helps!!

4 0

2 years ago

PLEASE HELP GIVING 20 PTS!!!!!! For circle H, JN = 3, NK = x, LN = 2, and NM = 6. Solve for x. PLEASE HEEELLLLPPPPPPP!!!!!!!

Marina CMI [18]

Answer:

x=9

Step-by-step explanation:

when two chords intersects each other, then the product of their segments is equal.

JNxNK = LN x NM

3 *x = 2 * 6

x = (3*6)/2 = 18/2 = 9

5 0

2 years ago

A bag contains 5 2/5kg of sand. The bag has a hole in it. Every 10 minutes, 1 2/3kg of sand escapes from the bag. After 20 minut

fenix001 [56]

Quantify of sand in a bag =

$= \: 5 \frac{2}{5} \ \:$

$= \frac{(5 \times 5 +2) }{5}$

$= \frac{27}{5} \: kg$

Quantity of sand that escapes in every 10 minutes :-

$= 1 \frac{2}{3} kg$

Quantity of sand that will escape in 20 minutes :-

$= 1 \frac{2}{3} \times 2$

$= \frac{(3 \times 1 + 2)}{3} \times 2$

$= \frac{5}{3} \times 2$

$= \frac{10}{3}$

Quantity of sand that will remain in the sand bag :-

$= \frac{27}{5} - \frac{10}{3}$

$= \frac{(27 \times 3)}{15} - \frac{(10 \times 5)}{15}$

$= \frac{81}{15} - \frac{50}{15}$

$= \frac{31}{15}$

$= 2 \frac{1}{5} \: kg$

$therefore \: , \: 2 \frac{1}{5} \: kg \: sand \: is \: left \: in \: the \: bag \: .$

3 0

2 years ago