<h3>I'll teach you how to solve 6 divided by -3/9</h3>
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6 divided by -3/9
Apply the fraction rule:
- 6/ 3/9
Apply the fraction rule:
-6*9/3
Multiply the numbers:
- 54/3
Divide the numbers:
-18
Your Answer Is -18
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Add 2 to both sdies
now if we can facor, then if
xy=0 then x and/or y=0
note:xy=x times y and x(y) =x times y
x^2+3x+2=0
what 2 number multiply to get 2 and add to get 3
the numbers are 2 and 1
(x+2)(x+1)=0
set them to zero
x+2=0
subtract 2
x=-2
x+1=0
subtract 1
x=-1
x could be -1 or -2
x=-2, or -1
Answer:
53/5
Step-by-step explanation:
Multiply both sides by 5: 5x - 3 = 50
Add 3 to both sides: 5x = 53
Divide both sides by 5: x = 53/5
Answer:
4d+2m+13
Step-by-step explanation:
Given the function f (x) = 3x, find the value of f-1 (81).
For this case, the first thing you should do is rewrite the function.
We have then:
y = 3 ^ x
From here, we clear the value of x:
log3 (y) = log3 (3 ^ x)
log3 (y) = x
Then, we rewrite the function again:
f (x) ^ - 1 = log3 (x)
Now, we evaluate the inverse function for x = 81:
f (81) ^ - 1 = log3 (81)
f (x) ^ - 1 = 4
Answer:
the value of f-1 (81) is:
f (x) ^ - 1 = 4