Answer:
The value of pressure at an altitude of 10000 ft = 10 
Step-by-step explanation:
Given data
Atmospheric pressure
= 14.7 
Pressure at 4000 ft = 12.6 
If temperature is constant then the atmospheric pressure is varies with the altitude according to law
P (h) =
------ (1)
where k= constant & h = height
12.6 = 14.7 
0.857 = 
㏑ 0.857 = - 4000 k
-0.154 = - 4000 k
k = 3.85 × 
Thus the atmospheric pressure at an altitude of 10,000 ft is
14.7 ×
----- (2)
Product of k & h is
k h = 3.85 ×
× 10000
k h = 0.385
Put his value of k h = 0.385 in equation (2) we get
14.7 × 
10 
This is the value of pressure at an altitude of 10000 ft.
Hi there!
If KLM is an isosceles triangle, then KM = LM.
4d - 13 = 12 - d
Solve for d. Add 'd' to both sides:
5d - 13 = 12
Add 13 to both sides:
5d = 25
Divide both sides by 5:
<u>d = 5 units.</u>
Answer:
D. 10
Step-by-step explanation:
To find the slope of the equation, we first need to put the equation into slope-intercept form:
y=mx+b
So first, we need to get y by itself.
10x-y=2
Subtract 10x from both sides.
-y=-10x+2
Then, divide -1 on both sides.
y=10x-2
Slope=10
The answer is 2.
it’s adding 2 everytime!