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3 years ago

Write 56x^2y as a prime factorization. show all of ur work.

Mathematics

1 answer:

Anastaziya [24]3 years ago

3 0

Answer:

–5(8x – 4y”) 5. a(4x” – 6y + 1) 6. c(2a + b + 3c) 7. x(3x” – 2x +5) 8. y(3x + 2y” + 4y) 9

Step-by-step explanation:

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3 years ago

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What type of triangle would have its orthocenter on the triangle?

Marizza181 [45]

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3 years ago

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4 years ago

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At the beginning of a study of individuals, 10% were classified as heavy smokers, 20% were classified as light smokers, and 70%

LUCKY_DIMON [66]

Answer: 0.39

Step-by-step explanation:

Given the following classification :

Heavy smokers (H) = 10%

Light smokers (L) = 20%

Non smokers (N) = 70%

Given that :

The death rates of the heavy and light smokers were five and three times that of the nonsmokers, respectively

Let probability of death = D

P(D | N) = d

P(D | H) = 5d

P(D | L) = 3d

Hence,

P(D) = [P(H) * P(D | H) + P(L) * P(D | L) + P(N) * P(D | N)]

P(D) = [0.1 * 5d + 0.2 * 3d + 0.7 * d]

P(D) = [0.5d + 0.6d + 0.7d]

P(D) = 1.8d

A randomly selected participant died over the five-year period: calculate the probability that the participant was a nonsmoker.

P(N | D) = [P(N) * P(D | N)] / P(D)

P(N | D) = 0.7d / 1.8d

P(N | D) = 0.3888

= 0.39

4 0

3 years ago

For 300 trading days, the daily closing price of a stock (in $) is well modeled by a Normal model with mean $196.99 and stand

KATRIN_1 [288]

Answer:

a) 2.5% b) 84% c) 95% d) D. The more unusual day is if the stock closed below $185 because it has the largest absolute z-score.

Step-by-step explanation:

For a) b) and c) we will use the empirical rule, so, we can observe the image shown below

a) 211.23 is exactly two standard deviation above the mean, so, the probability that on a randomly selected day in this period the stock price closed above 211.23 is 2.35% + 0.15% = 2.5%

b) 204.11 represents exactly one standard deviation above the mean, so, the probability of being below 204.11 is 50% + 34% = 84%

c) The probability of getting a value between 182.75 and 211.23 is 95%, this because 182.75 is exactly two standard deviations below the mean and 211.23 is exactly two standard deviations above the mean.

d) The z-score related to 208 is $z_{1}$ = (208-196.99)/7.12 = 1.5 and the z-score related to 185 is $z_{2}$ = (185-196.99)/7.12 = -1.7, therefore, the more unusual day is if the stock closed below $185 because it has the largest absolute z-score.

5 0

3 years ago