Answer:
QH = 227.8 km ≅ 228 km
Step-by-step explanation:
∵ The bearing from H to P is 084°
∵ The bearing from P to Q is 210°
∵ The distance from H to P = 340 km
∵ The distance from P to Q = 160 km
∴ The angle between 340 and 160 = 360 - 210 - (180 - 84) = 54°
( 180 - 84) ⇒ interior supplementary
By using cos Rule:
(QH)² = (PH)² + (PQ)² - 2(PH)(PQ)cos∠HPQ
(QH)² = 340² + 160² - 2(340)(160)cos(54) = 51904.965
∴ QH = 227.8 km ≅ 228 km
Answer:
1/2
Step-by-step explanation:
If you need the y intercept its (0,1)
so wt's the question of this pic?
9514 1404 393
Answer:
r ≈ 19.0
s ≈ 17.7
Step-by-step explanation:
The relevant trig relations are ...
Sin = Opposite/Hypotenuse
Cos = Adjacent/Hypotenuse
So, you have ...
cos(43°) = r/26
r = 26·cos(43°) ≈ 19.0
__
sin(43°) = s/26
s = 26·sin(43°) ≈ 17.7
