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Harrizon [31]
2 years ago
12

3. Write 13 tens as hundredsand tens.I hundreds 3 tens​

Mathematics
1 answer:
beks73 [17]2 years ago
5 0

Answer:

1 ten and 3 ones

Step-by-step explanation:

ten + three is 13. Hence, one ten and three ones.

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Another geometry question! Help!
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30-60-90 triangle are set up as the shorter side being x. The longer side is x times √3. The hypotenuse is 2 times x. 

So if your short side is 6, we do 6 times √3. This becomes 6√3, the first option. 
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3 years ago
Which two numbers should be placed in the blanks below so that the difference between consecutive numbers is the same?
IceJOKER [234]
<span>numbers is the same? 1<span>7,_,_,41 i think

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3 years ago
Can you put 5(3+j+2j) as a verbal expression?
liraira [26]

"Five times the sum of three, J, and two times J."

_____

Why would you want to? The math expression is much more concise and less likely to be misinterpreted.

5 0
3 years ago
A large box of jelly beans weighs 96.58 lb the jelly beans are evenly divided into 22 bags what is the weight in pounds of the j
Vadim26 [7]

Answer:

The weight in each bag is 4.39lb.

Step-by-step explanation:

To solve this, you simply need to divide 96.58 by 22. The reason you do this is so that way you can divide all of the weight into 22 bags.

96.58 ÷ 22 = 4.39

This means that the weight in each bag is 4.39lb.

4 0
2 years ago
The game of Connex contains one 4-unit piece, two identical 3-unit pieces, three identical 2-unit pieces and four identical 1-un
Aleks [24]

Answer: 277 ways

Step-by-step explanation:

Let’s start bycreating 10-unit pieces using the 4-unit piece.

The arrangements are:

1). 4-3-3 (3 permutations)

2). 4-3-2-1 = 4! = 24 permutations.

3). 4-3-1-1-1 (5*[4!/(3!1!)]

= 5*4

= 20permutations

4). 4-2-2-2 (4 permutations)

5). 4-2-2-1-1 (5 *[4!/(2!2!)]

= 5*6

= 30 permutations

6). 4-2-1-1-1-1(6*[5!/(4!1!)]

= 6*5

= 30 permutations

Let’s-consider the arrangements using one or more3-unit pieces and no 4-unit piece:

7). 3-3-2-2 (4!/(2!2!)

8). 3-3-2-1-1 (5*(4!/(2!2!)

= 5*6

= 30 permutations.

9). 3-3-1-1-1-1 (6!/(4!2!) = 0

10). 3-2-2-2-1 (5*4!/(3!1!)

= 5*4

= 20permutations

11). 3-2-2-1-1-1 (6*5!/(3!2!)

= 6*10

= 60 permutations

Finally we would look at the arrangements using only 1-and 2-unit pieces:

12). 2-2-2-1-1-1-1 (7!/(4!3!)

= 35 permutations

add them all up:

(3 + 24 + 20 + 4) + (30 + 30 + 6 + 30) + (15 + 20 + 60 + 35)

=51 + 96 + 130

= 277ways

5 0
2 years ago
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