If we want to select a ball of each colour we have to extract 175+150+75+70+1=471 balls
P=471/500 is the answer
Answer:
yes
Step-by-step explanation:
The line intersects each parabola in one point, so is tangent to both.
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For the first parabola, the point of intersection is ...
y^2 = 4(-y-1)
y^2 +4y +4 = 0
(y+2)^2 = 0
y = -2 . . . . . . . . one solution only
x = -(-2)-1 = 1
The point of intersection is (1, -2).
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For the second parabola, the equation is the same, but with x and y interchanged:
x^2 = 4(-x-1)
(x +2)^2 = 0
x = -2, y = 1 . . . . . one point of intersection only
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If the line is not parallel to the axis of symmetry, it is tangent if there is only one point of intersection. Here the line x+y+1=0 is tangent to both y^2=4x and x^2=4y.
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Another way to consider this is to look at the two parabolas as mirror images of each other across the line y=x. The given line is perpendicular to that line of reflection, so if it is tangent to one parabola, it is tangent to both.
Answer:
(6, -2)
Step-by-step explanation:
The midpoint of the segment RS is point M (5, 3). Therefore, the average of the x coordinates of R and S is 5, and the average of the y coordinates of R and S is 3. The x coordinate of R is 4. For 4 and the x coordinate of S to have an average of 5, the x coordinate of S must be 6. Therefore, our point is of the form (6, y). For 8 and the y coordinate of S to have an average of 3, the y coordinate of S must be -2. Therefore, our answer is (6, -2)
Answer:
B
Step-by-step explanation:
because the denominator of fraction, 5/12 ,is greater than both the numerator and the multiplier which is 7