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3 years ago

9

What values of P and Q have exactly no solutions Px+40=Qx+20

1 answer:

Novosadov [1.4K]3 years ago

6 0

You can not solve this because the values are different... If the values were both Px and Px or Qx and Qx you will be able to solve the problem but you can not according to the fact that they aren't the same letters. So therefore, this equation has no solution.

Hope this helped!!!

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If 4 + 6 = 10, does (4 + 6) X 3= 10 X 3? Why or why not?

spayn [35]

Answer: Yes, they equal

Explanation: (4 + 6) x 3 = 30 ; 10 x 3 = 30, 30 = 30

3 0

2 years ago

Solve: log(2)(3x + 8) = 5 Which is an equivalent equation?

Rzqust [24]

You can just simplify to make an equivalent equation:

(2)(3x + 8) = 5 ⇒ 6x + 16 = 5

Answer:

$\boxed{\bf~6x + 16 = 5}$

Hope it helped,

BioTeacher101

<em>(If you have any questions feel free to ask them in the comments)</em>

8 0

3 years ago

Read 2 more answers

tommy is buying used books for school. the price of the books is $180. he uses the 30%-off student discount and there is a 4% sa

zaharov [31]

Answer:

131.04

Step-by-step explanation:

0.7×180=126

1.04×126=131.04

7 0

3 years ago

Miriam is picking out some movies to rent, and she is primarily interested in comedies and foreign films. She has narrowed down

Keith_Richards [23]

Answer:

There are 795 combinations.

Step-by-step explanation:

The number of ways or combinations in which we can select k element from a group of n elements is given by:

$nCk=\frac{n!}{k!(n-k)!}$

So, if Miriam want to choose 3 movies with at least two comedies, she have two options: Choose 2 comedies and 1 foreign film or choose 3 comedies.

Then, the number of combinations for every case are:

1. Choose 2 Comedies from the 10 and choose 1 foreign film from 15. This is calculated as:

$10C2*15C1=\frac{10!}{2!(10-8)!}*\frac{15}{1!(15-14)!}$

$10C2*15C1=675$

2. Choose 3 Comedies from the 10. This is calculated as:

$10C3=\frac{10!}{3!(10-3)!}=120$

Therefore, there are 795 combinations and it is calculated as:

675 + 120 = 795

8 0

3 years ago

100-99+98-97+96-95...2-1=

Simora [160]

100-99=1+98=99-97=2+96=98-95=3
2-1=1

5 0

3 years ago