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ololo11 [35]
2 years ago
10

Find the exact value of sin(2) under given condition

Mathematics
1 answer:
Natasha2012 [34]2 years ago
6 0

Answer:

sin(a + b) = sinacosb + cosasinb;

tana = 20/21, then cosa = - 1/√1 + (20/21)2 = - 21/29, sina = tanacosa = 20/21·(- 21/29) = - 20/29;

sinb = √1 - (- 4/5)2 = 3/5

sin(a + b) = - 20/29·(-4/5) + (- 21/29)·3/5 = 80/145 - 63/145 = 17/145

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Find the vertex and y intercept of the quadratic function​
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Answer:  5) Vertex = (2, 28)   y-intercept = 40  → (0, 40)

               6) Vertex = (2, 11)     y-intercept = 7    → (0, 7)

<u>Step-by-step explanation:</u>

The y-intercept of the equation is when x = 0. It is the c-value when given in standard form: y = ax² + bx + c

To find the vertex, use the Axis of Symmetry equation to find the x-value

x = -b/(2a). Then plug the x-value into the equation to find the y-value.

5) y = 3x² - 12x + 40

         ↓       ↓       ↓

     a=3    b= -12  c=40

\text{AOS:}\quad x=\dfrac{-b}{2a}\quad =\dfrac{-(-12)}{2(3)}\quad =\dfrac{12}{6}\quad =2

Min:  y = 3(2)² - 12(2) + 40

           = 3(4)  - 24 + 40

           = 12 - 24 + 40

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Vertex: (2, 28)    y-intercept = 40

*******************************************************************************************

6) y = -x² + 4x + 7

         ↓      ↓      ↓

    a= -1    b=4  c=7

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About $17.05,
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Answer:

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