There are two correct answers. Numbers 3 4 are both correct. The sum of all angles in a triangle must add up to 180°. The two given where are 40° and 52°. If you subtract these from 180°, the remaining angle would be 88°. Choices 3 and4 both give two possible angles.
Answer:
Well I'm not sure if this is what your questions wants but, ok when a number divide itself it will always be one, therefore
2/2, 3/3, 4/4, 5/5, u can keep going
Answer:
40degrees
Step-by-step explanation:
Find the diagram attached
Since the triangle ina semi circle is a right angle, hence <B = 90degrees
Also frm the diagram
<A + <B + <C = 180
<A + 90 + 50 = 180
<A + 140 = 180
<A = 180 - 140
<A = 40degrees
Hence the measure if m<BAC is 40degrees
Area of sector is 17.584 meters
<em><u>Solution:</u></em>
Given that we have to find the approximate area of a sector given O= 56 degrees with a diameter of 12m
Diameter = 12 m
Radius = Diameter / 2 = 6 m
An angle of 56 degrees is the fraction
of the whole rotation
A sector of a circle with a sector angle of 56 degrees is therefore also the fraction
of the circle
The area of the sector will therefore also be
of the area
![\text{ sector area } = \frac{56}{360} \times \pi r^2\\\\\text{ sector area } = \frac{56}{360} \times 3.14 \times 6^2\\\\\text{ sector area } = 17.584](https://tex.z-dn.net/?f=%5Ctext%7B%20sector%20area%20%7D%20%3D%20%5Cfrac%7B56%7D%7B360%7D%20%5Ctimes%20%5Cpi%20r%5E2%5C%5C%5C%5C%5Ctext%7B%20sector%20area%20%7D%20%3D%20%5Cfrac%7B56%7D%7B360%7D%20%5Ctimes%203.14%20%5Ctimes%206%5E2%5C%5C%5C%5C%5Ctext%7B%20sector%20area%20%7D%20%3D%2017.584)
Thus area of sector is 17.584 meters
So you have to add all the numbers to get the perimeter or the outside distance but it looks like t and s is there a few times so that’s were you have to simplify.
So here’s the answer simplified
4t+2s+w+v+x+u
Good luck!