Answer:
the expected rate of change in consumption is 11.83
Step-by-step explanation:
The computation of the expected rate of change in consumption is shown below:
= (Expected quadrillion thermal units - 2003 quadrillion thermal units) ÷ (difference in years)
= (563 - 421) ÷ (2015 - 2003)
= 142 ÷ 12
= 11.83
hence, the expected rate of change in consumption is 11.83
We simply applied the above formula so that the correct value could come
And, the same is to be considered
Answer:
x= 30 degrees
Step-by-step explanation:
This is an isosceles triangle as indicates by the lines on the sides.
Since the sides lengths are equal, the base angles are equal
x= 30 degrees
Answer:c
Step-by-step explanation:just did the test
Answer:
C. 5.8 × 
Step-by-step explanation:
0.000058
4 zeros
4 + 1 = 5
5.8 × 10⁻5
If inspection department wants to estimate the mean amount with 95% confidence level with standard deviation 0.05 then it needed a sample size of 97.
Given 95% confidence level, standard deviation=0.05.
We know that margin of error is the range of values below and above the sample statistic in a confidence interval.
We assume that the values follow normal distribution. Normal distribution is a probability that is symmetric about the mean showing the data near the mean are more frequent in occurence than data far from mean.
We know that margin of error for a confidence interval is given by:
Me=
α=1-0.95=0.05
α/2=0.025
z with α/2=1.96 (using normal distribution table)
Solving for n using formula of margin of error.

n=
=96.4
By rounding off we will get 97.
Hence the sample size required will be 97.
Learn more about standard deviation at brainly.com/question/475676
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The given question is incomplete and the full question is as under:
If the inspection division of a county weights and measures department wants to estimate the mean amount of soft drink fill in 2 liters bottles to within (0.01 liter with 95% confidence and also assumes that standard deviation is 0.05 liter. What is the sample size needed?