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slega [8]
3 years ago
10

A circle of center (-3 , -2) passes through the points (0 , -6) and (a , 0). Find a. Pls

Mathematics
2 answers:
Schach [20]3 years ago
7 0

Answer:

(-4.5,0)

Step-by-step explanation:

ZanzabumX [31]3 years ago
6 0

Answer:

It passes through the point (3,4). Given that the center of the circle is the point (0,0). We know that the equation of the circle is given by : (x-a)^2 + (y-b)^2 = r^2 where (a,b) is the center and r is the radius.

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Answer:

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Step-by-step explanation:

Carolyn's work is incorrect. Below is the correct solution:

Given:

3x - 2y = 7 ----› Equation 1

y = x + 2 -----› Equation 2

Substitute y = (x + 2) in equation 1

3x - 2y = 7 ----› Equation 1

3x - 2(x + 2) = 7 (substitution)

3x - 2(x) -2(+2) = 7 (distributive property)

[Note: this is where Carolyn made a mistake]

3x - 2x - 4 = 7

Collect like terms

x - 4 = 7

x = 7 + 4 (addition property of equality).

x = 11

Substitute x = 11 in equation 2

y = x + 2 -----› Equation 2

y = 11 + 2 (substitution)

y = 13

✅The solution to the system of equations would be:

(11, 13)

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