All categories

3 years ago

Trapezoid ABCD was dilated to create trapezoid A’B’C’D’. Which statements are true about the trapezoids? Select three options

Mathematics

1 answer:

zvonat [6]3 years ago

5 0

The 3 options--1, 2, and 4.

You might be interested in

Beth purchased 7 sandwiches and spent a total of $43.75. If each sandwich was the same price, what was the cost per sandwich?

Alexus [3.1K]

Answer:

6.25 dont fake ur grade plz

Step-by-step explanation:

6 0

3 years ago

Which of the following equations is of the parabola whose vertex is at (2, 3), axis of symmetry parallel to the y-axis and p = 4

lora16 [44]

Answer:

option A.) y-3 = 1/16 (x-2)^2

Step-by-step explanation:

we know that

If the axis of symmetry is parallel to the y-axis, then we have a vertical parabola

The equation of a vertical parabola is equal to

$4p(y-k)=(x-h)^{2}$

where

(h,k) is the vertex

In this problem we have

(h,k)=(2,3)

p=4

substitute

$4(4)(y-3)=4(4)(x-2)^{2}$

$16(y-3)=(x-2)^{2}$

$(y-3)=(1/16)(x-2)^{2}$

8 0

3 years ago

Help needed ASAP will give you BRAINLIEST and 5 stars rate

iVinArrow [24]

I believe it is context clues. The reader typically looks for context clues to understand the reading.

5 0

3 years ago

SO anyways :))))

artcher [175]

Answer:

1 / 8², B

Step-by-step explanation:

8 / 8³

8³ = 8*8*8

So, the equation can also be written as:

8 / 8*8*8

divide the numerator and denominator by 8.

1 / 8*8

This is equal to:

1 / 8²

The answer is B.

7 0

3 years ago

Which of the following is the equation for the graph shown?a. x^2/144+y^2/95=1b. x^2/144-y^2/95=1c. x^2/95+y^2/144=1d. x^2/95-y^

Andrews [41]

e follSOLUTION

Given the question in the image, the following are the solution steps to answer the question

STEP 1: Write the general equation of an ellipse

$\frac{\mleft(x-h\mright)^2}{a^2}+\frac{(y-h)^2}{b^2^{}}=1$

STEP 2: Identify the parameters

the length of the major axis is 2a

the length of the minor axis is 2b

$\begin{gathered} 2a=24,a=\frac{24}{2}=12 \\ 2b=20,b=\frac{20}{2}=10 \end{gathered}$

STEP 3: Get the equation of the ellipse

$\begin{gathered} By\text{ substitution,} \\ \frac{(x-h)^2}{a^2}+\frac{(y-h)^2}{b^2}=1 \\ \frac{(x-0)^2}{12^2}+\frac{(y-0)^2}{10^2}=1=\frac{x^2}{144}+\frac{y^2}{100}=1 \end{gathered}$

STEP 4: Pick the nearest equation from the options,

Hence, the equation of the ellipse in the image is given as:

$\frac{x^2}{144}+\frac{y^2}{95}=1$

OPTION A

8 0

1 year ago