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2 years ago

7

hunter has a jar of 368 nickels and dimes. the total value of coins is $28.40. which system of equations below would be the best

to use to find the number of nickels and dimes hunter has?

1 answer:

gavmur [86]2 years ago

4 0

Answer:

We can't see your answer choices, but it would be n + d = 368 and .05n + .10d = 28.40

Step-by-step explanation:

You might be interested in

ANSWER ASAP ITS FOR FINALS

Roman55 [17]

Answer:

9. 66°

10. 44°

11. $2\sqrt{7}$

12. $2\sqrt{3}$

13. 27.3

14. 33.9

15. 22°

16. 24°

Step-by-step explanation:

9. Add 120 + 80 (equals 200) and subtract that from 360 (Because all angles in a quadrilteral add to 360°), this equals 160. Plug the same number in for both variables in the two other angle equations until the two angles add to 160. For shown work on #9, write:

120 + 80 = 200

360 - 200 = 160

12(5) + 6 = 66°

19(5) - 1 = 94°

94 + 66 = 160

10. Because the two sides are marked as congruent, the two angles are as well. This means the unlabeled angle is also 68°. The interior angles of a triangle always add to 180°, so add 68+68 (equals 136) and subtract that from 180, this equals 44. For shown work on #10, write:

68 x 2 = 136

180 - 136 = 44

11. Use the Pythagorean theorem (a² + b² = c²) (Make sure to plug in the hypotenuse for c). Solve the equation. For shown work on #10, write:

a² + b² = c²

a² + 6² = 8²

a² + 36 = 64

a² = 28

a = $\sqrt{28}$

a = $2\sqrt{7}$

12. (Same steps as #11) Use the Pythagorean theorem (a² + b² = c²) (Make sure to plug in the hypotenuse for c). Solve the equation. For shown work on #11, write:

a² + b² = c²

a² + 2² = 4²

a² + 4 = 16

a² = 12

a = $\sqrt{12}$

a = $2\sqrt{3}$

13. Use SOH CAH TOA and solve with a scientific calculator. For shown work on #13, write:

Sin(47°) = $\frac{20}{x}$

x = 27.3

14. Use SOH CAH TOA and solve with a scientific calculator. For shown work on #14, write:

Tan(62°) = $\frac{x}{18}$

x = 33.9

15. Use SOH CAH TOA and solve with a scientific calculator. For shown work on #15, write:

cos(θ) = 52/56

θ = cos^-1 (0.93)

θ = 22°

16. (Same steps as #15) Use SOH CAH TOA and solve with a scientific calculator. For shown work on #16, write:

sin(θ) = 4/10

θ = sin^-1 (0.4)

θ = 24°

Good luck!!

8 0

3 years ago

Instructions:Select the correct answer from each drop-down menu. ∆ABC has vertices at A(11, 6), B(5, 6), and C(5, 17). ∆XYZ has

Akimi4 [234]

to compare the triangles, first we will determine the distances of each side

<span>Distance = ((x2-x1)^2+(y2-y1)^2)^0.5
</span>Solving

<span>∆ABC A(11, 6), B(5, 6), and C(5, 17)</span>

<span>AB = 6 units BC = 11 units AC = 12.53 units
</span><span>∆XYZ X(-10, 5), Y(-12, -2), and Z(-4, 15)
</span><span>XY = 7.14 units YZ = 18.79 units XZ = 11.66 units</span>

<span>∆MNO M(-9, -4), N(-3, -4), and O(-3, -15).</span>

<span>MN = 6 units   NO = 11 units MO = 12.53 units
</span><span>∆JKL J(17, -2), K(12, -2), and L(12, 7).
</span><span>JK = 5 units   KL = 9 units JL = 10.30 units
</span><span>∆PQR P(12, 3), Q(12, -2), and R(3, -2)
</span><span>PQ = 5 units   QR = 9 units PR = 10.30 units</span>
Therefore
<span>we have the <span>∆ABC and the </span><span>∆MNO </span><span>
with all three sides equal</span> ---------> are congruent
</span><span>we have the <span>∆JKL </span>and the <span>∆PQR
</span>with all three sides equal ---------> are congruent </span>

let's check

Two plane figures are congruent if and only if one can be obtained from the other by a sequence of rigid motions (that is, by a sequence of reflections, translations, and/or rotations).

1) If ∆MNO ---- by a sequence of reflections and translation --- It can be obtained ------->∆ABC

<span> then </span>∆MNO<span> ≅</span> <span>∆ABC </span>

a) Reflexion (x axis)

The coordinate notation for the Reflexion is (x,y)---- >(x,-y)

<span>∆MNO M(-9, -4), N(-3, -4), and O(-3, -15).</span>

<span>M(-9, -4)-----------------> M1(-9,4)</span>

N(-3, -4)------------------ > N1(-3,4)

O(-3,-15)----------------- > O1(-3,15)

b) Reflexion (y axis)

The coordinate notation for the Reflexion is (x,y)---- >(-x,y)

<span>∆M1N1O1 M1(-9, 4), N1(-3, 4), and O1(-3, 15).</span>

<span>M1(-9, -4)-----------------> M2(9,4)</span>

N1(-3, -4)------------------ > N2(3,4)

O1(-3,-15)----------------- > O2(3,15)

c) Translation

The coordinate notation for the Translation is (x,y)---- >(x+2,y+2)

<span>∆M2N2O2 M2(9,4), N2(3,4), and O2(3, 15).</span>

<span>M2(9, 4)-----------------> M3(11,6)=A</span>

N2(3,4)------------------ > N3(5,6)=B

O2(3,15)----------------- > O3(5,17)=C

<span>∆ABC A(11, 6), B(5, 6), and C(5, 17)</span>

∆MNO reflection------- > ∆M1N1O1 reflection---- > ∆M2N2O2 translation -- --> ∆M3N3O3

The ∆M3N3O3=∆ABC

<span>Therefore ∆MNO ≅ <span>∆ABC - > </span>check list</span>

2) If ∆JKL -- by a sequence of rotation and translation--- It can be obtained ----->∆PQR

<span> then </span>∆JKL ≅ <span>∆PQR </span>

d) Rotation 90 degree anticlockwise

The coordinate notation for the Rotation is (x,y)---- >(-y, x)

<span>∆JKL J(17, -2), K(12, -2), and L(12, 7).</span>

<span>J(17, -2)-----------------> J1(2,17)</span>

K(12, -2)------------------ > K1(2,12)

L(12,7)----------------- > L1(-7,12)

e) translation

The coordinate notation for the translation is (x,y)---- >(x+10,y-14)

<span>∆J1K1L1 J1(2, 17), K1(2, 12), and L1(-7, 12).</span>

<span>J1(2, 17)-----------------> J2(12,3)=P</span>

K1(2, 12)------------------ > K2(12,-2)=Q

L1(-7, 12)----------------- > L2(3,-2)=R

∆PQR P(12, 3), Q(12, -2), and R(3, -2)

∆JKL rotation------- > ∆J1K1L1 translation -- --> ∆J2K2L2=∆PQR

<span>Therefore ∆JKL ≅ <span>∆PQR - > </span><span>check list</span></span>

6 0

3 years ago

C+2c+12=75 find the value of c

tamaranim1 [39]

Answer:

c+2c+12=75

c = 21

Steps:

c+2c+12=75

Simplify both sides of the equation.

c+2c+12=75

(c+2c)+(12)=75(Combine Like Terms)

3c+12=75

3c+12=75

Subtract 12 from both sides.

3c+12−12=75−12

3c=63

Divide both sides by 3.

3 0

3 years ago

The derivative of y with respect to x, when y = 3e^5x - 2 is:

Ede4ka [16]

Answer: 15e^5x

Step - by - step

y=3e^5x - 2

By the sum rule, the derivative of 3e^5x - 2 with respect to x is d/dx [ 3e^5x ] + d/dx [-2].

d/dx [ 3e^5x ] + d/dx [ -2 ]

Evalute d/dx [ 3e^5x ]

Since 3 is constant with respect to x , the derivative of 3e^5x with respect to x is
3 d/dx [ e^5x ].

3 d/dx [ e^5x ] + d/dx [ -2 ]

Differentiate using the chain rule, which states that d/dx [ f(g(x))] is f' (g(x)) g' (x) where f(x) = e^x and g(x) = 5x.

To apply the Chain Rule, set u as 5x.
3 ( d/du [ e^u] d/dx [5x] ) + d/dx [ -2]

Differentiate using the Exponential rule which states that d/du [ a^u ] is a^u ln(a) where a=e.

3( e^u d/dx[5x] ) + d/dx [ -2 ]
Replace
3(e^5x d/dx [5x] ) + d/dx [ -2 ]
3(e^5x( 5 d/dx [x] )) + d/dx [ -2 ]

Diffentiate using the Power Rule which states that d/dx [x^n] is nx^n-1 where n=1.
3(e^5x(5*1)) + d/dx [-2]
3 ( e^5x * 5 ) + d/dx [-2]

Multiply 5 by 3
15e^5x + d/dx [-2]

Since -2 is constant with respect to x, the derivative of -2 with respect to x is 0.
15e^5x + 0
15e^5x

5 0

1 year ago

Order the following numbers from least to greatest.

Simora [160]

Answer:

-53, -24, 0, 18

Step-by-step explanation:

Hope this helps :)

5 0

3 years ago

Read 2 more answers