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spin [16.1K]
3 years ago
11

David is standing 500 feet away from the base of a cell phone tower. The angle of elevation from his eyes to the top of the towe

r is 78 degrees. If David’s eyes are 6 feet above the ground, how tall is the tower?
Mathematics
1 answer:
andrey2020 [161]3 years ago
4 0

Answer:

height of the tower = 2358.3 feet

Step-by-step explanation:

To solve this question, we can use the tangent relation of the angle of elevation, where the opposite side of the angle is the height of the tower minus six feet and the adjacent side of the angle is the distance from David to the tower. So, we have that:

tangent(78) = (height - 6)/500

4.7046 = (height - 6) / 500

height - 6 = 2352.3

height = 2358.3 feet

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