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Setler [38]
3 years ago
9

Find four smallest positive numbers theta such that cosine = 1/2

Mathematics
1 answer:
bagirrra123 [75]3 years ago
3 0
Cos(x)=0.5
x=pi/3
since cos is postive in the fourth quadrant and first quadrant
x=pi/3+2*pi*k where k is an integer
fourth quadrant
x=(-pi/3)+2*pi*k where k is an integer
the first 3 values of K in the first quadrant are
pi/3,7*pi/3,13*pi/3
the first three postive values for the fourth quadrant are
5*pi/3,11*pi/3,19*pi/3

so the smallest three are
pi/3,5*pi/3,7*pi/3,11*pi/3
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Question:<br> Image Below
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Answer:

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Step-by-step explanation:

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5 0
2 years ago
Choose the expression that would equal the number of hours in the following question.
Minchanka [31]
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5 0
3 years ago
What error did zacharias make?
qwelly [4]
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The errors he made: he mistakenly used the negative (-) and postive (+)
      * -5 should have been 5
      * 52 should have been -52
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7 0
3 years ago
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I would really appreciate some help on this.
8_murik_8 [283]

Answer:

1. terms: 4r, 2, -6, and 3r        like terms: 2 and -6, 4r and 3r

2.terms: 5h^2, -3h^2, - 4h, 3h, 7       like terms: 5h^2 and -3h^2, - 4h and 3h

3. 3m + 6

4. 15b + 2

5. 3x + 9

Step-by-step explanation:

1. 4r + 2 - 6 +3r

  terms: 4r, 2, -6, and 3r                     like terms: 2 and -6, 4r and 3r

2. 5h^2 - 3h^2 - 4h + 3h + 7

   terms: 5h^2, -3h^2, - 4h, 3h, 7       like terms: 5h^2 and -3h^2, - 4h and 3h

3. 6m + 7 - 3m-1

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4. 3(5b +2) - 4

   15b + 6 - 4

   15b + 2

5. 2x + 4 + 5 + x

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5 0
3 years ago
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