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Setler [38]
3 years ago
9

Find four smallest positive numbers theta such that cosine = 1/2

Mathematics
1 answer:
bagirrra123 [75]3 years ago
3 0
Cos(x)=0.5
x=pi/3
since cos is postive in the fourth quadrant and first quadrant
x=pi/3+2*pi*k where k is an integer
fourth quadrant
x=(-pi/3)+2*pi*k where k is an integer
the first 3 values of K in the first quadrant are
pi/3,7*pi/3,13*pi/3
the first three postive values for the fourth quadrant are
5*pi/3,11*pi/3,19*pi/3

so the smallest three are
pi/3,5*pi/3,7*pi/3,11*pi/3
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Answer:

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Step-by-step explanation:

<u>The line with points (1,2) and (-1,-8). Work out its equation.</u>

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3 years ago
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Please help me answer question B!
skelet666 [1.2K]

Answer:

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Step-by-step explanation:

The specific contents of any of these registers at any point in time <em>depends on the architecture of the computer</em>. If we make the assumption that the only interface registers connected to memory are the memory address register (MAR) and the memory data register (MDR), then <em>all memory transfers of any kind</em> will use both of these registers.

For execution of the instructions at addresses 01 through 03, the sequence of operations may go like this.

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Answer:

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Step-by-step explanation:

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When you compare the form to your specific instance, you need to pay attention to what it is that you're comparing. As the attachment shows, ...

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Hence the vertex is (h, k) = (5, 6). The second attachment shows this on a graph.

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