Answer:
B. ![x^2+11x+24\leq 150](https://tex.z-dn.net/?f=x%5E2%2B11x%2B24%5Cleq%20150)
Step-by-step explanation:
<u>Step 1) </u><u><em>Defining Sue and Jeremy's ages using x</em></u>
Sue is 3 years older than Holly (<em>h</em>):
![h=x+3](https://tex.z-dn.net/?f=h%3Dx%2B3)
Jeremy is 5 years older than Sue, or 8 years older than Holly (<em>j</em>):
![j=x+8](https://tex.z-dn.net/?f=j%3Dx%2B8)
Product of Jeremy and Sue's ages is less than or equal to 150:
![hj\leq 150](https://tex.z-dn.net/?f=hj%5Cleq%20150)
<u>Step 2)</u><u><em> Simplifying into a single equation</em></u>
Using the equation above we can substitute Sue and Jeremy's ages:
![(x+3)(x+8)\leq 150](https://tex.z-dn.net/?f=%28x%2B3%29%28x%2B8%29%5Cleq%20150)
Now we can simplify this equation. Use the distributive property first:
![x(x+8)=x^2+8x\\3(x+8)=3x+24](https://tex.z-dn.net/?f=x%28x%2B8%29%3Dx%5E2%2B8x%5C%5C3%28x%2B8%29%3D3x%2B24)
Now add all the terms together and get the final answer:
![x^2+8x+3x+24\leq 150\\x^2+11x+24\leq 150](https://tex.z-dn.net/?f=x%5E2%2B8x%2B3x%2B24%5Cleq%20150%5C%5Cx%5E2%2B11x%2B24%5Cleq%20150)
Final equation: ![x^2+11x+24\leq 150](https://tex.z-dn.net/?f=x%5E2%2B11x%2B24%5Cleq%20150)