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kow [346]
2 years ago
13

Please help!!!! find the slope with the qord band above ! show me the work please !!​

Mathematics
1 answer:
bekas [8.4K]2 years ago
4 0

Answer:

1. Slope is 2

2. slope is 1/4

3. Slope is undefined

4. Slope is -1/2

5. slope is 0

6. Slope is 3/2

Step-by-step explanation:

for example:  the y intercept is -3. The next point is (1, -1) you rose 2 and ran (went over) 1. 2/1 is 2

you do the same for all of them.

Undefined is when it goes continuously downward.

the slope is 0 when it is perfectly horizontal.

I hope this helps

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Answer: 68

Step-by-step explanation: Complementary angles are angles that add up to 90. So, you need to do 90-22=68.

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2 years ago
 A tree casts a shadow that is about 10 ft long. Javier, who is about 5 ft tall, is standing near the tree. Javier’s shadow is a
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How many solutions are there to this system of equations?
Zinaida [17]

Answer:

one

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5 0
3 years ago
Write each ratio in simplest fractional form. 1. 16 dogs and 9 cats 2. 99 miles to 6 gallons 3. 4 frogs to 9 lily pads 4. 6 cups
soldi70 [24.7K]

Answer:

1. 16/9

2. 33/2

3. 4/9

4. 3/2

5. 6/13

Step-by-step explanation:

1. 16 dogs and 9 cats  

16/9

2. 99 miles to 6 gallons  

99/6

Divide by 3 on the top and bottom

33/2

3. 4 frogs to 9 lily pads

4/9

4. 6 cups of milk to 4 cups of flour

6/4

Divide the top and bottom by 2

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5. 6 girls to 13 boys

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6 0
3 years ago
5^(2x-1)+5^(x+1)=250<br> how do you solve?<br> thank you
zepelin [54]

Answer:

<em>x = 2</em>

Step-by-step explanation:

<u>Exponential Equations</u>

Solve:

5^{2x-1}+5^{x+1}=250

Separate each exponential:

5^{2x}5^{-1}+5^{x}5^{1}=250

Operating:

\displaystyle \frac{5^{2x}}{5}+5^{x}5=250

Multiplying by 5:

5^{2x}+25\cdot5^x=1250

Rearranging:

5^{2x}+25\cdot5^x-1250=0

Recall that:

5^{2x}=(5^{x})^2

(5^{x})^2+25\cdot5^x-1250=0

Calling

y=5^{x}:

y^2+25y-1250=0

Factoring:

(y-25)(y+50)=0

There are two possible solutions:

y=25

y=-50

Since

y=5^{x}

y cannot be negative, thus:

5^{x}=25=5^2

The solution is:

x = 2

8 0
3 years ago
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