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Salsk061 [2.6K]
3 years ago
13

Find the area of the following composite figure: A circle with a area of 50 inches, a rectangle with an area of 75 inches, and a

square with an area of 20 inches. ***HINT: since we have the areas, all we have to do is add the areas of each shape to find the composite area.​
Mathematics
1 answer:
Maslowich3 years ago
6 0

Answer:

145 inches

Step-by-step explanation:

Area of the circle = 50 inches

Area of the rectangle = 75 inches

Area of the square = 20 inches

Composite area = Area of the circle + Area of the rectangle + Area of the square

= 50 inches + 75 inches + 20 inches

= 145 inches

Composite area = 145 inches

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What is the area of the trapezoid?
Maslowich
<h3><u>Given Information :</u></h3>

  • Length of parallel sides = 60 ft and 40 ft
  • Height of the trapezoid = 30 ft

<h3><u>To calculate :</u></h3>

  • Area of the trapezoid.

<h3><u>Calculation :</u></h3>

As we know that,

\bigstar \: \boxed{\sf {Area_{(Trapezium)} = \dfrac{1}{2} \times ( a + b) \times h}} \\

  • a and b are length of parallel sides.
  • h denotes height.

<em>S</em><em>u</em><em>b</em><em>s</em><em>t</em><em>i</em><em>t</em><em>u</em><em>t</em><em>i</em><em>n</em><em>g</em><em> </em><em>valu</em><em>es</em><em>,</em><em> </em><em>we</em><em> </em><em>get</em><em> </em>:

\longmapsto Area = \sf \dfrac{1}{2} × ( 60 + 40 ) × 30 ft\sf ^2

\longmapsto Area = \sf \dfrac{1}{2} × 100 × 30 ft\sf ^2

\longmapsto Area = 1 × 100 × 15 ft\sf ^2

\longmapsto Area = 100 × 15 ft\sf ^2

\longmapsto <u>Area = 1500 ft</u>\sf ^2

Therefore,

  • Area of the trapezoid is <u>1500 ft\sf ^2</u>

6 0
2 years ago
Word form for 607.409
ivann1987 [24]
Six hundred seven and four hundred nine one-thousandths. 
6 0
3 years ago
Read 2 more answers
How many students must be randomly selected to estimate the mean weekly earnings of students at one college? We want 95% confide
kari74 [83]

Answer:

The sample of students required to estimate the mean weekly earnings of students at one college is of size, 3458.

Step-by-step explanation:

The (1 - <em>α</em>)% confidence interval for population mean (<em>μ</em>) is:

CI=\bar x\pm z_{\alpha/2}\times \frac{\sigma}{\sqrt{n}}

The margin of error of a (1 - <em>α</em>)% confidence interval for population mean (<em>μ</em>) is:

MOE=z_{\alpha/2}\times \frac{\sigma}{\sqrt{n}}

The information provided is:

<em>σ</em> = $60

<em>MOE</em> = $2

The critical value of <em>z</em> for 95% confidence level is:

z_{\alpha/2}=z_{0.05/2}=z_{0.025}=1.96

Compute the sample size as follows:

MOE=z_{\alpha/2}\times \frac{\sigma}{\sqrt{n}}

       n=[\frac{z_{\alpha/2}\times \sigma }{MOE}]^{2}

          =[\frac{1.96\times 60}{2}]^{2}

          =3457.44\\\approx 3458

Thus, the sample of students required to estimate the mean weekly earnings of students at one college is of size, 3458.

8 0
2 years ago
angle works at AutoZone and makes $72 dollars a day and extra $8 for each platinum membership card he sells. angles goal is to m
GenaCL600 [577]

Angle needs to sell 16 membership cards.

First, I subtracted 72 from 200 and that gave me 128. Then, I divided 128 by 8 and got 16. To check my work I multiplied 16 by 8 and got 128. Then I added 72 to 128 and got 200.

Hope this helps!

7 0
3 years ago
Which value of x makes the equation 1.25(6x - 20) = 50 true?
bixtya [17]
D. X = 10

6x-20= 40

6x=40+20

6x=60

X=10
4 0
2 years ago
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