<h3><u>Given Information :</u></h3>
- Length of parallel sides = 60 ft and 40 ft
- Height of the trapezoid = 30 ft
<h3><u>To calculate :</u></h3>
<h3><u>Calculation :</u></h3>
As we know that,

- a and b are length of parallel sides.
- h denotes height.
<em>S</em><em>u</em><em>b</em><em>s</em><em>t</em><em>i</em><em>t</em><em>u</em><em>t</em><em>i</em><em>n</em><em>g</em><em> </em><em>valu</em><em>es</em><em>,</em><em> </em><em>we</em><em> </em><em>get</em><em> </em>:
Area =
× ( 60 + 40 ) × 30 ft
Area =
× 100 × 30 ft
Area = 1 × 100 × 15 ft
Area = 100 × 15 ft
<u>Area = 1500 ft</u>
Therefore,
- Area of the trapezoid is <u>1500 ft
</u>
Six hundred seven and four hundred nine one-thousandths.
Answer:
The sample of students required to estimate the mean weekly earnings of students at one college is of size, 3458.
Step-by-step explanation:
The (1 - <em>α</em>)% confidence interval for population mean (<em>μ</em>) is:

The margin of error of a (1 - <em>α</em>)% confidence interval for population mean (<em>μ</em>) is:

The information provided is:
<em>σ</em> = $60
<em>MOE</em> = $2
The critical value of <em>z</em> for 95% confidence level is:

Compute the sample size as follows:

![n=[\frac{z_{\alpha/2}\times \sigma }{MOE}]^{2}](https://tex.z-dn.net/?f=n%3D%5B%5Cfrac%7Bz_%7B%5Calpha%2F2%7D%5Ctimes%20%5Csigma%20%7D%7BMOE%7D%5D%5E%7B2%7D)
![=[\frac{1.96\times 60}{2}]^{2}](https://tex.z-dn.net/?f=%3D%5B%5Cfrac%7B1.96%5Ctimes%2060%7D%7B2%7D%5D%5E%7B2%7D)

Thus, the sample of students required to estimate the mean weekly earnings of students at one college is of size, 3458.
Angle needs to sell 16 membership cards.
First, I subtracted 72 from 200 and that gave me 128. Then, I divided 128 by 8 and got 16. To check my work I multiplied 16 by 8 and got 128. Then I added 72 to 128 and got 200.
Hope this helps!
D. X = 10
6x-20= 40
6x=40+20
6x=60
X=10