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Rudiy27
3 years ago
11

Ik a) but I need help with b)

Mathematics
1 answer:
lozanna [386]3 years ago
8 0

Answer:

{ \rm{ {( \frac{1}{ \sqrt{3} }) }^{7} }} \\

• First rationalise the denominator:

= { \rm{ {( \frac{1 \times  \sqrt{3} }{ \sqrt{3} \times  \sqrt{3}  }) }^{7} }} \\  \\  = { \rm{ {( \frac{ \sqrt{3} }{3}) }^{7} }}

• Open the bracket, by distributing the power to both the numerator and denominator:

= { \rm{ \frac{( \sqrt{3} ) {}^{6} \times  \sqrt{3}  }{ {3}^{7} } }} \\  \\  = { \rm{ \frac{27 \sqrt{3} }{2187} }} \\  \\   = { \rm{ \frac{ \sqrt{3} }{81} }}

b is 3 and c is 81

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