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3 years ago

Help!!!!!!!!!! Please!!!!!!!

Mathematics

1 answer:

alukav5142 [94]3 years ago

3 0

Answer:

Collin mistake is step 1

correct answer $\frac{3x - 3}{x^{2} -3x}$

Step-by-step explanation:

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Ratio of 24 centimeters by 20 centimeters explanation

snow_tiger [21]

Dear MikeIlKell2002, what you can do is explain using cross products. Do 24/20=x/1 x=1.2.

4 0

4 years ago

A 11 cm 1000 с B 7 cm What is the approximate area of A ABC?

larisa [96]

Answer:

6.38384 cm

Step-by-step explanation:

Solution:

Area: 3.7552 ∙ 1.7 = 6.38384 cm 2

All digits are significant.

Answer:

6.38384 cm

6 0

3 years ago

How do you solve 10≤2x≤x+9? The answer says it's 5≤x≤9 but i have no idea how it got there

Tanya [424]

Answer:

Step-by-step explanation:

so why this kind of problem is so confusing is b/c it's 2 problems in one

if you were to expand this it look like this

10 ≤2x

and

2x ≤x+9

This is really saying.. that x has a range.. and that the 1st equations is the lower stop point, and that the 2nd equations is the upper stop point

once it's taken apart.. I bet you can solve it pretty quickly.

5≤x

and

x ≤9

then just put it back together in that confusing .. yet handy way to write it,

5≤x≤9

5 0

3 years ago

Subtract (3 + 2i) from (-9-81) 0 -17 – 51 0-6 – 67 0 -12 – 101 0 12 + 101

harkovskaia [24]

Answer:

-12 - 10i.

Step-by-step explanation:

-9 - 8i - (3 + 2i)

= -9 - 8i - 3 - 2i

= -12 - 10i.

3 0

3 years ago

Find the SUm of the infinite series.

givi [52]

I'll do problem 13 to get you started.

The expression $4\left(\frac{2^n}{7^n}\right)$ is the same as $4\left(\frac{2}{7}\right)^n$

Then we can do a bit of algebra like so to change that n into n-1

$4\left(\frac{2}{7}\right)^n\\\\4\left(\frac{2}{7}\right)^n*1\\\\4\left(\frac{2}{7}\right)^n*\left(\frac{2}{7}\right)^{0}\\\\4\left(\frac{2}{7}\right)^n*\left(\frac{2}{7}\right)^{1-1}\\\\4\left(\frac{2}{7}\right)^n*\left(\frac{2}{7}\right)^{1}*\left(\frac{2}{7}\right)^{-1}\\\\4*\left(\frac{2}{7}\right)^{1}\left(\frac{2}{7}\right)^n*\left(\frac{2}{7}\right)^{-1}\\\\\frac{8}{7}\left(\frac{2}{7}\right)^{n-1}\\\\$

This is so we can get the expression in a(r)^(n-1) form

a = 8/7 is the first term of the geometric sequence
r = 2/7 is the common ratio

Note that -1 < 2/7 < 1, which satisfies the condition that -1 < r < 1. This means the infinite sum converges to some single finite value (rather than diverge to positive or negative infinity).

We'll plug those a and r values into the infinite geometric sum formula below

S = a/(1-r)

S = (8/7)/(1 - 2/7)

S = (8/7)/(5/7)

S = (8/7)*(7/5)

S = 8/5

S = 1.6

------------------------

Answer in fraction form = 8/5

Answer in decimal form = 1.6

7 0

3 years ago