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2 years ago

Helpppppppppppppppppppppppppppppppppppppppppppppppppppp.

Mathematics

1 answer:

mina [271]2 years ago

8 0

Answer:

1 and 6 are like terms--true
8 is a factor--true
In 9u, 9 is a coefficient--true

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Please round 0.02623 to the nearest hundred. |||| Thank you guys! please answer soon!

ElenaW [278]

Answer:

0.03

Step-by-step explanation:

6 is greater then 5, so you add 1 to 2 making 0.03

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3 years ago

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Help! Is it parallel, perpendicular, or neither? Thanks *ignore handwriting*

Digiron [165]

These lines are perpendicular!
y = x
y = -x–2
The slopes are reciprocals of each other, so they are perpendicular.

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2 years ago

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If A and B are independent events with P(A) = .5 and P(B) = .2, find the following:a) P(A U B)b) P(A^c ? B^c)c) P(A^c U B^c)**No

Effectus [21]

If A and B are independent, then $P(A\cap B)=P(A)P(B)$ .

$P(A\cup B)=P(A)+P(B)-P(A\cap B)=P(A)+P(B)-P(A)P(B)$

$P(A\cup B)=0.5+0.2-0.5\cdot0.2$

$\boxed{P(A\cup B)=0.6}$

b. I'm guessing the ? is supposed to stand for intersection. We can use DeMorgan's law for complements here:

$P(A^c\cap B^c)=P(A\cup B)^c=1-P(A\cup B)$

$P(A^c\cap B^c)=1-0.6$

$\boxed{P(A^c\cap B^c)=0.4}$

c. DeMorgan's law can be used here too:

$P(A^c\cup B^c)=P(A\cap B)^c=1-P(A\cap B)=1-P(A)P(B)$

$P(A^c\cup B^c)=1-0.5\cdot0.2$

$\boxed{P(A^c\cup B^c)=0.9}$

4 0

2 years ago

-3(5x + 6) + 2 = 2(8 + 8x) - 1

bija089 [108]

So first, we multiply out the brackets.
-15x - 18 + 2 = 17 + 16x -1
Then, bring all the terms onto one side so you can solve.
-15x-18+2-17-16x+1=0
Then, we simplify this.
-31x-32=0
Then, isolate x
-31x=32
x=32/-31 or -1.03 (nearest hundredth )

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2 years ago

Can someone pls help me out

USPshnik [31]

Answer:

It is a money market account. So answer A.

Step-by-step explanation:

3 0

3 years ago

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