Ask question

Ask question

All categories

3 years ago

13

W+2/3=2 5/6 what is w

1 answer:

Oduvanchick [21]3 years ago

6 0

Answer:

13/6

Step-by-step explanation:

2 5/6=17/6

w+2/3=17/6

w=17/6-2/3

w=17/6-4/6

w=13/6

You might be interested in

Can someone please help me with this question

Anton [14]

It seems the first line has to be

1. AB=CD and AD=CB 1. given

2. AC=AC 2. Reflexivity (things are equal to themselves)

3 $\triangle$ ACB $\cong$ $\triangle$ CAD 3. SSS

4. $\angle$ 1 = $\angle$ 4. Corresponding parts of congruent triangles

5 DC || AB 5. Congruent alternate traversal angles imply parallel lines

5 0

3 years ago

. Sara collected $135 in donations for the hospital. This represents 5% of the total amount collected by her class. How much did

AfilCa [17]

5 percent of 2700 is 135 so the answer is $2700

6 0

3 years ago

Read 2 more answers

(7^0)^x = 1 what is x ?

Nataly_w [17]

7^0 = 1
1^x = 1
x = 0

5 0

3 years ago

Which series of transformations will not map figure H onto itself

7nadin3 [17]

Answer:

D

Step-by-step explanation:

Given a square with vertices at points (2,1), (1,2), (2,3) and (3,2).

Consider option A.

1st transformation $(x+0,y-2)$ will map vertices of the square into points

$(2,1)\rightarrow (2,-1);$
$(1,2)\rightarrow (1,0);$
$(2,3)\rightarrow (2,1);$
$(3,2)\rightarrow (3,0).$

2nd transformation = reflection over y = 1 has the rule (x,2-y). So,

$(2,-1)\rightarrow (2,3);$
$(1,0)\rightarrow (1,2);$
$(2,1)\rightarrow (2,1);$
$(3,0)\rightarrow (3,2)$

These points are exactly the vertices of the initial square.

Consider option B.

1st transformation $(x+2,y-0)$ will map vertices of the square into points

$(2,1)\rightarrow (4,1);$
$(1,2)\rightarrow (3,2);$
$(2,3)\rightarrow (4,3);$
$(3,2)\rightarrow (5,2).$

2nd transformation = reflection over x = 3 has the rule (6-x,y). So,

$(4,1)\rightarrow (2,1);$
$(3,2)\rightarrow (3,2);$
$(4,3)\rightarrow (2,3);$
$(5,2)\rightarrow (1,2)$

These points are exactly the vertices of the initial square.

Consider option C.

1st transformation $(x+3,y+3)$ will map vertices of the square into points

$(2,1)\rightarrow (5,4);$
$(1,2)\rightarrow (4,5);$
$(2,3)\rightarrow (5,6);$
$(3,2)\rightarrow (6,5).$

2nd transformation = reflection over y = -x + 7 will map vertices into points

$(5,4)\rightarrow (3,2);$
$(4,5)\rightarrow (2,3);$
$(5,6)\rightarrow (1,2);$
$(6,5)\rightarrow (2,1)$

These points are exactly the vertices of the initial square.

Consider option D.

1st transformation $(x-3,y-3)$ will map vertices of the square into points

$(2,1)\rightarrow (-1,-2);$
$(1,2)\rightarrow (-2,-1);$
$(2,3)\rightarrow (-1,0);$
$(3,2)\rightarrow (0,-1).$

2nd transformation = reflection over y = -x + 2 will map vertices into points

$(-1,-2)\rightarrow (4,3);$
$(-2,-1)\rightarrow (3,4);$
$(-1,0)\rightarrow (2,3);$
$(0,-1)\rightarrow (3,2)$

These points are not the vertices of the initial square.

5 0

3 years ago

6=1-2n+5 can you please solve it

stepan [7]

Answer:

n = 0

Step-by-step explanation:

6 = 1 - 2n + 5

6 = 6 -2n

0 = -2n

n = 0

3 0

3 years ago

Read 2 more answers