Please help me thank you.
1 answer:
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Answer:
see explanation
Step-by-step explanation:
15
JK + KL = JL , substitute values
2x + 1 + 6x = 81, that is
8x + 1 = 81 ( subtract 1 from both sides )
8x = 80 ( divide both sides by 8 )
x = 10
Thus JK = 2x + 2 = 2(10) + 1 = 20 + 1 = 21
KL = 6x = 6 × 10 = 60
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16
JK + KL = JL , substitute values
2x + x + 2 = 5x - 10 , that is
3x + 2 = 5x - 10 ( subtract 3x from both sides )
2 = 2x - 10 ( add 10 to both sides )
12 = 2x ( divide both sides by 2 )
6 = x
Thus
JK = 2X = 2 × 6 = 12
KL = x + 2 = 6 + 2 = 8
JL = 5x - 10 = 5(6) - 10 = 30 - 10 = 20
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17
Calculate the distance d using the distance formula
d =
with (x₁, y₁ ) = S(7, 3) and (x₂, y₂ ) = T(1, - 5)
d =
=
=
= = 10
See picture hope it helps
Answer:
a). ∠D = 56°
b). AD = √13
Step-by-step explanation:
(a) From the figure attached, ABCD is a trapezoid with parallel sides AB and CD. We have to find the measure of ∠D from the given figure.
From triangle ADE,
D =
D = 56.31
D ≈ 56°
Therefore, measure of ∠D is 56°.
(b). Now by applying Pythagoras theorem in ΔADE,
AD² = AE² + DE²
= 3² + 2²
AD² = 9 + 4
AD = √13
Length of AD is √13 in.
