Answer:
Step-by-step explanation:
9.6
= 12.14314621
19.6 ÷ 1.6 = 12.25
Answer:
Step-by-step explanation:
66=2(w+5)+2w L=14+5
66=2w+10+2w L=19
66=4w+10
-10
56=4w/4
14=w
Answer:
241,920 different ways
Step-by-step explanation:
We have 6 vowels, but A repeats twice and I repeats three times, so the number of ways in which each can either start or end the word:
³P₂ = 3! / (3 - 2)! = 6 / 1 = 6 ways
You can start words with A, E or I, or end the words with A, E, or I.
the remaining 8 consonants can be arranged in 8! ways = 40,320 ways
total number of ways that the letters can be arranged = 6 x 40,320 = 241,920 different ways
Answer:
÷ ![\frac{1}{16}](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7B16%7D)
(check your other question for my explanation)