The answer to #5 is y=x-2/3+4
Answer:
(a) The probability that a randomly selected alumnus would say their experience surpassed expectations is 0.05.
(b) The probability that a randomly selected alumnus would say their experience met or surpassed expectations is 0.67.
Step-by-step explanation:
Let's denote the events as follows:
<em>A</em> = Fell short of expectations
<em>B</em> = Met expectations
<em>C</em> = Surpassed expectations
<em>N</em> = no response
<u>Given:</u>
P (N) = 0.04
P (A) = 0.26
P (B) = 0.65
(a)
Compute the probability that a randomly selected alumnus would say their experience surpassed expectations as follows:
Thus, the probability that a randomly selected alumnus would say their experience surpassed expectations is 0.05.
(b)
The response of all individuals are independent.
Compute the probability that a randomly selected alumnus would say their experience met or surpassed expectations as follows:
Thus, the probability that a randomly selected alumnus would say their experience met or surpassed expectations is 0.67.
The answer is “95”
All you have to do to figure this out is Take both numbers and divide them
Ex.) 855/9 = 95
Pentagons have five sides, so 5*7 is 35 units