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Ber [7]
3 years ago
5

Please help homework due in 30 min

Mathematics
2 answers:
Delvig [45]3 years ago
8 0
I think it’s A but to be honest I haven’t work one of these problems in a while so I’m not 100% sure!
dimulka [17.4K]3 years ago
7 0

Answer: D

9x - 12

Step-by-step explanation:

3(2x-4)+3x

Use the distributive property

6x-12+3x

Then combine like terms

9x-12

SO THE ANSWER IS D

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3.
Vitek1552 [10]
To solve this we are going to use the future value of annuity due formula: FV=(1+ \frac{r}{n} )*P[ \frac{(1+ \frac{r}{n})^{kt}-1 }{ \frac{r}{n} } ]
where
FV is the future value
P is the periodic deposit 
r is the interest rate in decimal form 
n is the number of times the interest is compounded per year
k is the number of deposits per year

We know for our problem that P=420 and t=15. To convert the interest rate to decimal form, we are going to divide the rate by 100%: r= \frac{10}{100} =0.1. Since Ruben makes the deposits every 6 months, k=2. The interest is compounded semiannually, so 2 times per year; therefore, k=2.
Lets replace the values in our formula:

FV=(1+ \frac{r}{n} )*P[ \frac{(1+ \frac{r}{n})^{kt}-1 }{ \frac{r}{n} } ]
FV=(1+ \frac{0.1}{2} )*420[ \frac{(1+ \frac{0.1}{2})^{(2)(15)}-1 }{ \frac{01}{2} } ]
FV=29299.53

We can conclude that the correct answer is <span>$29,299.53</span>
8 0
4 years ago
A cell phone provider offers a plan that costs ​$40 per month plus ​$0.20 per text message sent or received. A comparable plan c
GalinKa [24]
So what times .2 equals 20
100 messages
6 0
4 years ago
Read 2 more answers
I WILL GIVE BRAINLIEST!!!
zimovet [89]

Not equivalent to any of the given expressions.

Step-by-step explanation:

{7}^{2m} . {6}^{2m}  \\  \\  = (7.6) ^{2m}  \\  \\  =  {42}^{2m}

Hence, {42}^{2m} is not equivalent to any of the given expressions.

6 0
3 years ago
Read 2 more answers
The distance between two cities is 325 miles.
Papessa [141]
About 50 miles. hope this helps!
8 0
3 years ago
Read 2 more answers
Solve the system.
svetoff [14.1K]

Answer:

(0, 1)

General Formulas and Concepts:

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
  • Left to Right

Equality Properties

<u>Algebra I</u>

  • Solving systems of equations using substitution/elimination

Step-by-step explanation:

<u>Step 1: Define Systems</u>

y + 5x = 1

5y - x = 5

<u>Step 2: Rewrite Systems</u>

y + 5x = 1

  1. Subtract 5x on both sides:                    y = 1 - 5x

<u>Step 3: Redefine Systems</u>

y = 1 - 5x

5y - x = 5

<u>Step 4: Solve for </u><em><u>x</u></em>

<em>Substitution</em>

  1. Substitution in <em>y</em>:                      5(1 - 5x) - x = 5
  2. Distribute 5:                             5 - 25x - x = 5
  3. Combine like terms:                5 - 26x = 5
  4. Isolate <em>x</em> term:                          -26x = 0
  5. Isolate <em>x</em>:                                   x = 0

<u>Step 5: Solve for </u><em><u>y</u></em>

  1. Define equation:                    5y - x = 5
  2. Substitute in <em>x</em>:                       5y - 0 = 5
  3. Subtract:                                 5y = 5
  4. Isolate <em>y</em>:                                 y = 1
8 0
3 years ago
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