To solve this we are going to use the future value of annuity due formula:
![FV=(1+ \frac{r}{n} )*P[ \frac{(1+ \frac{r}{n})^{kt}-1 }{ \frac{r}{n} } ]](https://tex.z-dn.net/?f=FV%3D%281%2B%20%5Cfrac%7Br%7D%7Bn%7D%20%29%2AP%5B%20%5Cfrac%7B%281%2B%20%5Cfrac%7Br%7D%7Bn%7D%29%5E%7Bkt%7D-1%20%7D%7B%20%5Cfrac%7Br%7D%7Bn%7D%20%7D%20%5D)
where

is the future value

is the periodic deposit

is the interest rate in decimal form

is the number of times the interest is compounded per year

is the number of deposits per year
We know for our problem that

and

. To convert the interest rate to decimal form, we are going to divide the rate by 100%:

. Since Ruben makes the deposits every 6 months,

. The interest is compounded semiannually, so 2 times per year; therefore,

.
Lets replace the values in our formula:
![FV=(1+ \frac{r}{n} )*P[ \frac{(1+ \frac{r}{n})^{kt}-1 }{ \frac{r}{n} } ]](https://tex.z-dn.net/?f=FV%3D%281%2B%20%5Cfrac%7Br%7D%7Bn%7D%20%29%2AP%5B%20%5Cfrac%7B%281%2B%20%5Cfrac%7Br%7D%7Bn%7D%29%5E%7Bkt%7D-1%20%7D%7B%20%5Cfrac%7Br%7D%7Bn%7D%20%7D%20%5D)
![FV=(1+ \frac{0.1}{2} )*420[ \frac{(1+ \frac{0.1}{2})^{(2)(15)}-1 }{ \frac{01}{2} } ]](https://tex.z-dn.net/?f=FV%3D%281%2B%20%5Cfrac%7B0.1%7D%7B2%7D%20%29%2A420%5B%20%5Cfrac%7B%281%2B%20%5Cfrac%7B0.1%7D%7B2%7D%29%5E%7B%282%29%2815%29%7D-1%20%7D%7B%20%5Cfrac%7B01%7D%7B2%7D%20%7D%20%5D)
We can conclude that the correct answer is <span>
$29,299.53</span>
Not equivalent to any of the given expressions.
Step-by-step explanation:

Hence,
is not equivalent to any of the given expressions.
About 50 miles. hope this helps!
Answer:
(0, 1)
General Formulas and Concepts:
<u>Pre-Algebra</u>
Order of Operations: BPEMDAS
- Brackets
- Parenthesis
- Exponents
- Multiplication
- Division
- Addition
- Subtraction
Equality Properties
<u>Algebra I</u>
- Solving systems of equations using substitution/elimination
Step-by-step explanation:
<u>Step 1: Define Systems</u>
y + 5x = 1
5y - x = 5
<u>Step 2: Rewrite Systems</u>
y + 5x = 1
- Subtract 5x on both sides: y = 1 - 5x
<u>Step 3: Redefine Systems</u>
y = 1 - 5x
5y - x = 5
<u>Step 4: Solve for </u><em><u>x</u></em>
<em>Substitution</em>
- Substitution in <em>y</em>: 5(1 - 5x) - x = 5
- Distribute 5: 5 - 25x - x = 5
- Combine like terms: 5 - 26x = 5
- Isolate <em>x</em> term: -26x = 0
- Isolate <em>x</em>: x = 0
<u>Step 5: Solve for </u><em><u>y</u></em>
- Define equation: 5y - x = 5
- Substitute in <em>x</em>: 5y - 0 = 5
- Subtract: 5y = 5
- Isolate <em>y</em>: y = 1