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Veronika [31]
3 years ago
15

I just need like a step by step I haven't understood what my teacher has taught me here ​

Mathematics
1 answer:
motikmotik3 years ago
7 0
You are trying to find the side between the right angle and the degree (This is known as the adjacent)
You are given degree 42
You also given the longest side of 19 (This is known as the hypothenuse)
Cosine: adjacent/hypothenuse
Cos42 = x/19
0.7431448255 = x/19
x = 19 * 0.7431448255
x = 14.11975168, round to tenth

Solution: x = 14.1
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2x - 3 > 15 or 3 + 7x < 17
Viktor [21]

Answer:

2x-3>15 and 3-7x>17 =  

3-7x>17

-7x>14

x<-2

Step-by-step explanation:

Sorry this is not a proper equation. I think you meant this equation.

2x-3>15 and 3-7x>17

for this equation the answer is

3-7x>17

-7x>14

x<-2

6 0
3 years ago
Question 2. Taylor is fertilizing her yard. She
sweet [91]
Answer is “D” I took the test my self
3 0
3 years ago
What is the perpendicular adjacent sides in the triangle
d1i1m1o1n [39]
"Adjacent" means next to each other. "Perpendicular" means at an angle of 90 degrees. 
<span>Rectangles (this includes squares) have adjacent perpendicular sides. So do right triangles.</span>
6 0
3 years ago
Read 2 more answers
Find the nth taylor polynomial for the function, centered at c. f(x) = ln(x), n = 4, c = 5
masha68 [24]

The nth taylor polynomial for the given function is

P₄(x) = ln5 + 1/5 (x-5) - 1/25*2! (x-5)² + 2/125*3! (x-5)³ - 6/625*4! (x - 5)⁴

Given:

f(x) = ln(x)

n = 4

c = 3

nth Taylor polynomial for the function, centered at c

The Taylor series for f(x) = ln x centered at 5 is:

P_{n}(x)=f(c)+\frac{f^{'} (c)}{1!}(x-c)+  \frac{f^{''} (c)}{2!}(x-c)^{2} +\frac{f^{'''} (c)}{3!}(x-c)^{3}+.....+\frac{f^{n} (c)}{n!}(x-c)^{n}

Since, c = 5 so,

P_{4}(x)=f(5)+\frac{f^{'} (5)}{1!}(x-5)+  \frac{f^{''} (5)}{2!}(x-5)^{2} +\frac{f^{'''} (5)}{3!}(x-5)^{3}+.....+\frac{f^{n} (5)}{n!}(x-5)^{n}

Now

f(5) = ln 5

f'(x) = 1/x ⇒ f'(5) = 1/5

f''(x) = -1/x² ⇒ f''(5) = -1/5² = -1/25

f'''(x) = 2/x³  ⇒ f'''(5) = 2/5³ = 2/125

f''''(x) = -6/x⁴ ⇒ f (5) = -6/5⁴ = -6/625

So Taylor polynomial for n = 4 is:

P₄(x) = ln5 + 1/5 (x-5) - 1/25*2! (x-5)² + 2/125*3! (x-5)³ - 6/625*4! (x - 5)⁴

Hence,

The nth taylor polynomial for the given function is

P₄(x) = ln5 + 1/5 (x-5) - 1/25*2! (x-5)² + 2/125*3! (x-5)³ - 6/625*4! (x - 5)⁴

Find out more information about nth taylor polynomial here

brainly.com/question/28196765

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3 0
2 years ago
On a scale drawing 2 centimeters represent 50 meters. How many centimeters represent 5 meters?
Tanya [424]

Answer:

0.2 centimeters

Step-by-step explanation:
Strategy 1:

Make the equation: 5=a•s, where s is the scale factor and "a" is the number of centimeters which 5 meters

First, we need to find the scale factor. 50 meters would be s times greater than 2 centimeters. Find s by first converting meters into centimeters
50m=5000cm. 5000cm=2cm*s, so s = 2500
5m=a*2500, a=0.002 meters, and 0.002 meters is equal to 0.2 centimeters.

Strategy 2:
the ratio of the scale drawing to real life will always stay the same, so
2 cm / 50 meters = x / 5 meters, and cross multiply to get
x cm* 50 m = 2 cm * 5 m, so
x cm * 10 = 2 cm
x cm = 2/10 cm
x cm = 0.2 cm

Strategy 3:
Notice that 5 meters is 10 times smaller than 50 meters, so on the scale drawing, we are looking for a number 10 times smaller than 2 centimeters, so  2/10=0.2 cm

8 0
2 years ago
Read 2 more answers
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