I think it would be 120 but i’m not 100% sure
Answer:
5/8
Step-by-step explanation:
Subtract the total computers from the old computers.
40-15=25
Then put the number of new computers over the total computers
25/40
Then, simplify
5/8
Answer:
Brenda
Step-by-step explanation:
You can divide the number of pages by the number of minutes to find the amount of minutes it takes to read 1 page. For Arnold, 3 pages / 7 minutes = 1 page per approximately 0.43 minutes. For Brenda, 8 pages / 14 minutes = 1 page per approximately 0.57 minutes. Brenda reads slightly faster since 0.57 > 0.43
For this case we have that by definition, the equation of a line in the slope-intersection form is:
![y = mx + b](https://tex.z-dn.net/?f=y%20%3D%20mx%20%2B%20b)
Where:
m: It is the slope
b: It is the cut point with the y axis
The slope is: ![m = \frac {2} {5}](https://tex.z-dn.net/?f=m%20%3D%20%5Cfrac%20%7B2%7D%20%7B5%7D)
Thus, the equation is of the form:
![y = \frac {2} {5} x + b](https://tex.z-dn.net/?f=y%20%3D%20%5Cfrac%20%7B2%7D%20%7B5%7D%20x%20%2B%20b)
We substitute the given point and find "b":
![-5 = \frac {2} {5} (- 5) + b\\-5 = -2 + b\\-5 + 2 = b\\b = -3](https://tex.z-dn.net/?f=-5%20%3D%20%5Cfrac%20%7B2%7D%20%7B5%7D%20%28-%205%29%20%2B%20b%5C%5C-5%20%3D%20-2%20%2B%20b%5C%5C-5%20%2B%202%20%3D%20b%5C%5Cb%20%3D%20-3)
Finally, the equation is:
![y = \frac {2} {5} x-3](https://tex.z-dn.net/?f=y%20%3D%20%5Cfrac%20%7B2%7D%20%7B5%7D%20x-3)
Answer:
![y = \frac {2} {5} x-3](https://tex.z-dn.net/?f=y%20%3D%20%5Cfrac%20%7B2%7D%20%7B5%7D%20x-3)
NO. The mirror will not fit in a space that is 15 inches by 16 inches
<em><u>Solution:</u></em>
Given that area of mirror is 225 square inches
![width = 13\frac{3}{4} \text{ inches }](https://tex.z-dn.net/?f=width%20%3D%2013%5Cfrac%7B3%7D%7B4%7D%20%5Ctext%7B%20inches%20%7D)
Converting the above mixed fraction we get,
![width = 13\frac{3}{4} = \frac{13 \times 4 + 3}{4} = \frac{55}{4} \text{ inches }](https://tex.z-dn.net/?f=width%20%3D%2013%5Cfrac%7B3%7D%7B4%7D%20%3D%20%5Cfrac%7B13%20%5Ctimes%204%20%2B%203%7D%7B4%7D%20%3D%20%5Cfrac%7B55%7D%7B4%7D%20%5Ctext%7B%20inches%20%7D)
Let us find the length of mirror
The area of mirror is given as:
area of mirror = length x width
Substituting the given values,
![225 = length \times \frac{55}{4}\\\\length = 225 \times \frac{4}{55}\\\\length = 225 \times 0.0727\\\\length = 16.36](https://tex.z-dn.net/?f=225%20%3D%20length%20%5Ctimes%20%5Cfrac%7B55%7D%7B4%7D%5C%5C%5C%5Clength%20%3D%20225%20%5Ctimes%20%5Cfrac%7B4%7D%7B55%7D%5C%5C%5C%5Clength%20%3D%20225%20%5Ctimes%200.0727%5C%5C%5C%5Clength%20%3D%2016.36)
Thus length of mirror is 16.36 inches
<em><u>Will the mirror fit in a space that is 15 inches by 16 inches?</u></em>
NO. The mirror will not fit in a space that is 15 inches by 16 inches
Because length of mirror is 16.36 inches whereas the given space is 15 inches long
16.36 > 15 so the length of mirror will not fit inside the space
Also width of mirror is
inches which is less than the given space whose width is 16 inches
13.75 < 16 so the width of mirror will not fit inside the space