10d+ 25q+5n= 805
D= n+8
Q= n+ 5
10d+ 25q+5n= 805
10(n+8)+25(n+5)+5n=805
10n+80+25n+125+5n=805
40n+205=805
40n=805-205
40n= 600
N=600/40
N= 15
D= n+8
D= 15+8
D= 23
Q=n+5
Q=15+5
Q=20
So 15 nickels ,23 dimes and 20quarters .
To check
15(0.05)= $0.75
23(0.10)=$2.30
20(0.25)=$5.00
Add it
5.00+2.30+0.75=8.05
7.30+.75=8.05
8.05=8.05
The chi-squared test statistic will be 3.11. The test statistic is contrasted with a predicted value based on the Chi-square distribution.
<h3>What is the chi-squared test statistic?</h3>
Finding the squared difference between the actual and anticipated data values, then dividing that difference by the expected data values, constitutes the test statistic.
The formula for the chi-squared test statistic is;
Where,
is the observed value
is the expected value
The chi-square test statics is;
Hence, the chi-squared test statistic will be 3.11.
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Answer:
I would say 60 students said that math was their favorite subject...
Step-by-step explanation:
<span>356 pounds minus 176 ounces equals 345 pounds</span>
The sampling that Joan is using is known as cluster sampling.
<h3>What is sampling?</h3>
It should be noted that sampling simply neans when a sample of a population is taken in order to illustrate the characteristics of the entire population.
In this case, the sampling that Joan is using is known as cluster sampling. This was depicted as she randomly select 10 flights from all available data in the past year.
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