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2 years ago

A dozen eggs cost $300 what will I pay for 9 eggs

Mathematics

1 answer:

const2013 [10]2 years ago

7 0

Answer:

225 dollars

Step-by-step explanation:

If a dozen eggs are 300 dollars altogether and, there are 12 eggs in a dozen you divide 300 by 12, to get the price of each egg individually, which would be 25 dollars per egg...

Then you multiply 25 times 9...

which would equal 225...

so, 9 eggs would be 225 dollars altogether!

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What is the following product? (5 square root 2-4 square root 3) (5 square root 2-4 square root 3)

Zina [86]

Answer:

(5 square root 2-4 square root 3) (5 square root 2-4 square root 3)

= 98 - 40 $\sqrt{6}$

Step-by-step explanation:

i) (5 $\sqrt{2}$ - 4 $\sqrt{3}$ ) × (5√2 - 4√3)

=(5 $\sqrt{2}$ × 5 $\sqrt{2}$ ) - (5 $\sqrt{2}$ × 4 $\sqrt{3}$ ) - (4 $\sqrt{3}$ × 5 $\sqrt{2}$ ) + (4 $\sqrt{3}$ × 4 $\sqrt{3}$ )

= 50 - 20 $\sqrt{6}$ - 20 $\sqrt{6}$ + 48

= 98 - 40 $\sqrt{6}$

8 0

3 years ago

Read 2 more answers

Can someone finish the whole thing ??

Romashka-Z-Leto [24]

<h3>Answer: y = (3/2)x + 0</h3>

This is the same as y = (3/2)x

=============================================================

Work Shown:

Find the slope of the line through (x1,y1) = (-2,-3) and (x2,y2) = (2,3)

m = (y2 - y1)/(x2 - x1)

m = (3 - (-3))/(2 - (-2))

m = (3 + 3)/(2 + 2)

m = 6/4

m = 3/2

The slope is the fraction 3/2. This is going to be in front of the x, or to the left of the x.

----------

Plug m = 3/2 and (x1,y1) = (-2,-3) into the point slope formula. Solve for y.

y - y1 = m(x - x1)

y - (-3) = (3/2)(x - (-2))

y + 3 = (3/2)(x + 2)

y + 3 = (3/2)x + (3/2)(2)

y + 3 = (3/2)*x + 3

y + 3 - 3 = (3/2)*x + 3 - 3

y = (3/2)x + 0

The y intercept is zero. This matches up with the fact the graph crosses the y axis at y = 0.

3 0

3 years ago

How can we get rid of i in the denominator?

Sloan [31]

Answer:

When you have an imaginary number in the denominator multiply the numerator and the denominator by the conjugate of the denominator.

8 0

3 years ago

A credit reporting agency claims that the mean credit card debt in a town is greater than $3500. A random sample of the credit c

Lera25 [3.4K]

Answer:

Claim is false

Step-by-step explanation:

Claim : A credit reporting agency claims that the mean credit card debt in a town is greater than $3500.

$H_0:\mu \leq 3500\\H_a:\mu = 3500$

n = 20

Since n <30

So we will use t test

Formula : $t =\frac{x-\mu}{\frac{s}{\sqrt{n}}}$

s = standard deviation = 391

x = 3600

n = 20

$t =\frac{3600-3500}{\frac{391}{\sqrt{20}}}$

$t =1.14$

Degree of freedom = n-1 = 20-1 = 19

α=0.10

So, using t table

$t_({\frac{\alpha}{2},d.f.})$ = 1.72

t critical > t calculated

So we accept the null hypothesis

Hence we reject the claim that the mean credit card debt in a town is greater than $3500.

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3 years ago

In which quadrant does point T (−5, 10) lie?

torisob [31]

Quadrant II.
Hope this helps.

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3 years ago